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Question

The sum of the age of A and 3 times the age of B is 43 years. When 5 times the age of A is added to 2 times the age of B, the result is 98 years. The sum of the ages (in years) of A and B is:

The correct answer is
25

Age Problem Explained: System of Equations Method

This problem involves finding the sum of the ages of two people, A and B, based on two given conditions relating their ages. We can solve this using a system of linear equations.

Setting Up the Age Equations

Let's represent the age of A as '$A$' and the age of B as '$B$'. We can translate the given information into two equations:

  • "The sum of the age of A and 3 times the age of B is 43 years." This translates to:

    $A + 3B = 43 \quad (1)$

  • "When 5 times the age of A is added to 2 times the age of B, the result is 98 years." This translates to:

    $5A + 2B = 98 \quad (2)$

Solving the System of Equations

We need to solve these two equations simultaneously to find the values of '$A$' and '$B$'. We can use the elimination method.

  1. Multiply Equation (1) to match A coefficients: Multiply the first equation by 5 so that the coefficient of '$A$' matches in both equations.

    $5 \times (A + 3B) = 5 \times 43$

    $5A + 15B = 215 \quad (3)$

  2. Eliminate A: Subtract Equation (2) from the new Equation (3).

    $(5A + 15B) - (5A + 2B) = 215 - 98$

    $5A + 15B - 5A - 2B = 117$

    $13B = 117$

  3. Solve for B: Divide both sides by 13.

    $B = \frac{117}{13}$

    $B = 9$

    So, the age of B is 9 years.

  4. Substitute B to find A: Substitute the value of '$B$' (which is 9) back into Equation (1).

    $A + 3(9) = 43$

    $A + 27 = 43$

  5. Solve for A: Subtract 27 from both sides.

    $A = 43 - 27$

    $A = 16$

    So, the age of A is 16 years.

Calculating the Sum of Ages

The question asks for the sum of the ages of A and B.

Sum = Age of A + Age of B

Sum = $A + B$

Sum = $16 + 9$

Sum = $25$

The sum of the ages of A and B is 25 years.

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Important Questions from Problem on Ages (Notes)

  1. At present, Sharad is three times as old as his son, and his daughter is 3 years younger than the son. If the sum of the ages of these three people 3 years ago was 63 years, then Sharad's present age (in years) is:
  2. A father said to his son, "I was as old as you are when I became your father." If the current age of father is 52 years, the age of son after 10 years will be___________.

  3. The sum of the age of A and 5 times the age of B is 55 years. When 3 times the age of A is added to 7 times the age of B, the result is 99 years. The sum of the ages (in years) of A and B is:
  4. Eight years ago, the age of the mother was four times the age of her son. Eight years hence, the mother's age will be two times the age of her son. Find the ratio of the present age of the mother to the age of the son.
  5. The sum of the age of A and 5 times the age of B is 36 years. When 3 times the age of A is added to 7 times the age of B, the result is 62 years. The sum of the ages (in years) of A and B is:
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