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Question

The difference between the squares of the ages (in complete years) of a father and his son is 899. The age of the father when his son was born

The correct answer is
is 29 years.

Understanding the Age Difference Problem

Let $F$ represent the father's current age and $S$ represent the son's current age, both in complete years.

The problem states that the difference between the squares of their ages is 899:

$F^2 - S^2 = 899$

We are asked to find the father's age when the son was born, which is equal to the difference between their current ages, $F - S$.

Factoring the Equation

We can use the difference of squares algebraic identity: $a^2 - b^2 = (a - b)(a + b)$.

Applying this to the problem:

$ (F - S)(F + S) = 899 $

Let $x = F - S$ (the age difference) and $y = F + S$ (the sum of their ages). The equation becomes:

$ x \cdot y = 899 $

Since $F$ and $S$ represent ages in complete years, they are positive integers. Therefore, $x$ and $y$ must be positive integer factors of 899.

Additionally, since $F > S$, $x = F - S$ must be positive. Also, $y = F + S > F - S = x$. So, we are looking for factor pairs $(x, y)$ of 899 such that $0 < x < y$.

Finding Integer Factors of 899

To find the factors, we can test prime numbers. We need to find the prime factorization of 899.

Testing divisions:

  • $899$ is not divisible by 3 (sum of digits is 26).
  • $899$ is not divisible by 5.
  • Trying larger primes: $899 \div 29 = 31$.

So, the prime factorization is $899 = 29 \times 31$.

The pairs of factors $(x, y)$ of 899, where $x < y$, are:

  • Pair 1: $(1, 899)$
  • Pair 2: $(29, 31)$

Calculating Possible Age Differences

We also know that $F = \frac{y + x}{2}$ and $S = \frac{y - x}{2}$. For $F$ and $S$ to be integers (representing ages), $x$ and $y$ must have the same parity (both must be odd or both must be even). Since their product $x \cdot y = 899$ is odd, both $x$ and $y$ must be odd.

Both factor pairs satisfy this condition:

Case 1: $x = 1, y = 899$

  • $F - S = 1$
  • $F + S = 899$
  • Adding these gives $2F = 900$, so $F = 450$.
  • Subtracting gives $2S = 898$, so $S = 449$.
  • This is a valid solution with an age difference of $1$ year.

Case 2: $x = 29, y = 31$

  • $F - S = 29$
  • $F + S = 31$
  • Adding these gives $2F = 60$, so $F = 30$.
  • Subtracting gives $2S = 2$, so $S = 1$.
  • This is also a valid solution with an age difference of $29$ years.

Determining the Correct Age Difference

The two possible age differences ($F - S$) are 1 year and 29 years.

Comparing these with the given options:

  • Option 1: cannot be ascertained
  • Option 2: 27 years
  • Option 3: 29 years
  • Option 4: 31 years

The calculated age difference of 29 years matches Option 3.

Therefore, the age of the father when his son was born is 29 years.

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Important Questions from Problem on Ages (Notes)

  1. At present, Sharad is three times as old as his son, and his daughter is 3 years younger than the son. If the sum of the ages of these three people 3 years ago was 63 years, then Sharad's present age (in years) is:
  2. A father said to his son, "I was as old as you are when I became your father." If the current age of father is 52 years, the age of son after 10 years will be___________.

  3. The sum of the age of A and 5 times the age of B is 55 years. When 3 times the age of A is added to 7 times the age of B, the result is 99 years. The sum of the ages (in years) of A and B is:
  4. The sum of the age of A and 3 times the age of B is 43 years. When 5 times the age of A is added to 2 times the age of B, the result is 98 years. The sum of the ages (in years) of A and B is:
  5. Eight years ago, the age of the mother was four times the age of her son. Eight years hence, the mother's age will be two times the age of her son. Find the ratio of the present age of the mother to the age of the son.
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