The difference between the squares of the ages (in complete years) of a father and his son is 899. The age of the father when his son was born
Let $F$ represent the father's current age and $S$ represent the son's current age, both in complete years.
The problem states that the difference between the squares of their ages is 899:
$F^2 - S^2 = 899$
We are asked to find the father's age when the son was born, which is equal to the difference between their current ages, $F - S$.
We can use the difference of squares algebraic identity: $a^2 - b^2 = (a - b)(a + b)$.
Applying this to the problem:
$ (F - S)(F + S) = 899 $
Let $x = F - S$ (the age difference) and $y = F + S$ (the sum of their ages). The equation becomes:
$ x \cdot y = 899 $
Since $F$ and $S$ represent ages in complete years, they are positive integers. Therefore, $x$ and $y$ must be positive integer factors of 899.
Additionally, since $F > S$, $x = F - S$ must be positive. Also, $y = F + S > F - S = x$. So, we are looking for factor pairs $(x, y)$ of 899 such that $0 < x < y$.
To find the factors, we can test prime numbers. We need to find the prime factorization of 899.
Testing divisions:
So, the prime factorization is $899 = 29 \times 31$.
The pairs of factors $(x, y)$ of 899, where $x < y$, are:
We also know that $F = \frac{y + x}{2}$ and $S = \frac{y - x}{2}$. For $F$ and $S$ to be integers (representing ages), $x$ and $y$ must have the same parity (both must be odd or both must be even). Since their product $x \cdot y = 899$ is odd, both $x$ and $y$ must be odd.
Both factor pairs satisfy this condition:
Case 1: $x = 1, y = 899$
Case 2: $x = 29, y = 31$
The two possible age differences ($F - S$) are 1 year and 29 years.
Comparing these with the given options:
The calculated age difference of 29 years matches Option 3.
Therefore, the age of the father when his son was born is 29 years.