The problem asks for the variance of a new set of values after each original value is increased by a constant. We are given the standard deviation of the original 12 values.
A fundamental property in statistics is that adding a constant value to every data point in a dataset does not change the dataset's spread or variability. This means the standard deviation and variance remain unchanged.
We are given:
According to the property mentioned above, the new standard deviation is the same as the old standard deviation:
$ \sigma_{new} = \sigma_{old} = 3 $
Variance is the square of the standard deviation ($\sigma^2$).
Therefore, the variance of the new set of values is:
$ \text{Variance}_{new} = (\sigma_{new})^2 $
$ \text{Variance}_{new} = (3)^2 $
$ \text{Variance}_{new} = 9 $
Thus, the variance of the new set of values is 9.
Calculate the standard deviation for the following data.
4, 7, 9, 10, 15
Calculate the mean from the following table.
Scores | Frequencies |
0-10 | 2 |
10-20 | 4 |
20-30 | 12 |
30-40 | 21 |
40-50 | 6 |
50-60 | 3 |
60-70 | 2 |
Find the standard deviation of the following data (rounded off to two decimal places).
5, 3, 4, 7
If the standard deviation of a population is 5, what will be its variance?
A. 10
B. 15
C. 25
D. 12.5
The variance of a set of data is 196. Then the standard deviation of the data is.
A. ± 14
B. 14
C. 96
D. 98The variance of a set of data is 144. Then the standard deviation of the data is:
A. ±12
B. 12
C. 44
D. 72