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Question

Following are the ages (in years) of 6 people in a group: 25, 30, 35, 40, 45 and 50. What is the standard deviation of their ages (rounded to two decimal places)?

The correct answer is
3. 8.54

Understanding Standard Deviation Calculation for Ages

This solution explains the step-by-step process to calculate the standard deviation for a given set of ages: 25, 30, 35, 40, 45, and 50 years. Standard deviation measures the amount of variation or dispersion of a set of values.

Step 1: Calculate the Mean (Average) of the Ages

First, we find the mean ($\mu$) of the given ages. The mean is the sum of all values divided by the total number of values.

The ages are: 25, 30, 35, 40, 45, 50.

Number of observations ($n$) = 6.

Sum of ages = $25 + 30 + 35 + 40 + 45 + 50 = 225$ years.

The formula for the mean is:

$$ \mu = \frac{\sum x_i}{n} $$

Calculating the mean:

$$ \mu = \frac{225}{6} = 37.5 \text{ years} $$

Step 2: Calculate the Deviations from the Mean

Next, we find the difference between each age and the mean ($\mu$).

Age ($x_i$) Deviation ($x_i - \mu$)
25 $25 - 37.5 = -12.5$
30 $30 - 37.5 = -7.5$
35 $35 - 37.5 = -2.5$
40 $40 - 37.5 = 2.5$
45 $45 - 37.5 = 7.5$
50 $50 - 37.5 = 12.5$

Step 3: Square the Deviations

Now, we square each of the deviations calculated in the previous step.

Deviation ($x_i - \mu$) Squared Deviation $(x_i - \mu)^2$
$-12.5$ $(-12.5)^2 = 156.25$
$-7.5$ $(-7.5)^2 = 56.25$
$-2.5$ $(-2.5)^2 = 6.25$
$2.5$ $(2.5)^2 = 6.25$
$7.5$ $(7.5)^2 = 56.25$
$12.5$ $(12.5)^2 = 156.25$

Step 4: Calculate the Variance

The variance ($\sigma^2$) is the average of the squared deviations. Since we are given a specific group of 6 people and asked for the standard deviation of *their* ages, we treat this as a population. Therefore, we divide the sum of squared deviations by the number of observations ($n$).

Sum of Squared Deviations = $156.25 + 56.25 + 6.25 + 6.25 + 56.25 + 156.25 = 437.5$

The formula for population variance is:

$$ \sigma^2 = \frac{\sum (x_i - \mu)^2}{n} $$

Calculating the variance:

$$ \sigma^2 = \frac{437.5}{6} \approx 72.9167 $$

Step 5: Calculate the Standard Deviation

The standard deviation ($\sigma$) is the square root of the variance.

The formula for population standard deviation is:

$$ \sigma = \sqrt{\sigma^2} $$

Calculating the standard deviation:

$$ \sigma = \sqrt{72.9167} \approx 8.5404 $$

Step 6: Round the Result

We need to round the standard deviation to two decimal places.

$$ \sigma \approx 8.54 $$

Therefore, the standard deviation of the ages is approximately 8.54 years.

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Important Questions from Standard Deviation

  1. Calculate the mean from the following table.

    Scores

    Frequencies

    0-10

    2

    10-20

    4

    20-30

    12

    30-40

    21

    40-50

    6

    50-60

    3

    60-70

    2

  2. Find the standard deviation of the following data (rounded off to two decimal places).

    5, 3, 4, 7

  3. If the standard deviation of a population is 5, what will be its variance?

    A. 10

    B. 15

    C. 25

    D. 12.5

  4. The variance of a set of data is 196. Then the standard deviation of the data is.

    A. ± 14

    B. 14

    C. 96

    D. 98
  5. The variance of a set of data is 144. Then the standard deviation of the data is:

    A. ±12

    B. 12

    C. 44

    D. 72

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