The square root of 5776 is:
76
The question asks us to find the square root of the number 5776. The square root of a number is a value that, when multiplied by itself, gives the original number. We are looking for a number 'x' such that \(x^2 = 5776\), or \(x = \sqrt{5776}\).
We can find the square root of 5776 using methods like prime factorization or the long division method for square roots. The long division method is often straightforward for finding the exact square root of a perfect square like 5776.
Here's how to calculate the square root of 5776 using the long division method:
The digits we found for the square root are 7 and 6. Therefore, the square root of 5776 is 76.
Let's verify the answer by squaring 76:
\(76 \times 76\)
We can calculate this as:
\[ \begin{array}{@{}c@{\,}c} & 76 \\ \times & 76 \\ \hline & 456 \quad (76 \times 6) \\ + & 5320 \quad (76 \times 70) \\ \hline & 5776 \\ \end{array} \]
The result is 5776, confirming that 76 is indeed the square root of 5776.
Based on the calculations, the square root of 5776 is 76.
| Step | Description | Result |
|---|---|---|
| 1 | Pair digits of 5776 | 57 76 |
| 2 | Find largest square $\le$ 57 | $7^2 = 49$ |
| 3 | First digit of root; subtract 49 from 57 | Root: 7; Remainder: 8 |
| 4 | Bring down next pair (76); number becomes 876 | Current number: 876 |
| 5 | Double root (7); find digit x for 14x * x $\le$ 876 | Try x=6; $146 \times 6$ |
| 6 | Calculate $146 \times 6$; subtract from 876 | $146 \times 6 = 876$; $876 - 876 = 0$ |
| 7 | Final root digit is 6 | Square Root: 76 |
| Term | Definition | Example |
|---|---|---|
| Square Root | A number that, when multiplied by itself, equals a given number. Represented by the symbol $\sqrt{ }$. | $\sqrt{25} = 5$ because $5 \times 5 = 25$. |
| Perfect Square | An integer that is the square of another integer. | 9 is a perfect square because $3^2 = 9$. |
| Radicand | The number inside the square root symbol. | In $\sqrt{5776}$, 5776 is the radicand. |
The long division method for square roots is based on the algebraic expansion of a binomial squared: \((a+b)^2 = a^2 + 2ab + b^2\). In each step of the long division, we are essentially finding the next digit (b) of the root, given the digits found so far (a). The process iteratively finds the digits of the root from left to right, subtracting the square of the root found so far and using the remaining value to find the next digit.
For example, finding $\sqrt{5776}$: Initial step finds 'a' where \(a^2 \le 57\). We found \(a=7\). So the root is around 70-80. The remaining part is \(5776 - 70^2 = 5776 - 4900 = 876\). Now we look for a number 70+b such that \((70+b)^2 \approx 5776\). \((70+b)^2 = 70^2 + 2 \times 70 \times b + b^2 = 4900 + 140b + b^2\). We have \(4900 + 140b + b^2 = 5776\). So, \(140b + b^2 = 5776 - 4900 = 876\). This can be written as \(b(140+b) = 876\). In the long division step, doubling the root found so far (7) gives 14, and appending the next digit 'b' gives 14b. Multiplying by 'b' gives \(b \times (140+b)\) because the 14 represents \(2 \times 70\). We find \(b=6\), as \(6 \times (140+6) = 6 \times 146 = 876\). This confirms the long division method is an application of this algebraic principle.
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