For the next two (02) items that follow: Consider a triangle ABC satisfying \(2{\rm{a}}{\sin ^2}\left( {\frac{{\rm{C}}}{2}} \right) + 2{\rm{c}}{\sin ^2}\left( {\frac{{\rm{A}}}{2}} \right) = 2{\rm{a}} + 2{\rm{c}} - 3{\rm{b}}\)
The sides of the triangle are in
A.P.
This problem asks us to determine the relationship between the sides of a triangle ABC given a specific trigonometric equation involving its sides and angles. The given equation is: \(2{\rm{a}}{\sin ^2}\left( {\frac{{\rm{C}}}{2}} \right) + 2{\rm{c}}{\sin ^2}\left( {\frac{{\rm{A}}}{2}} \right) = 2{\rm{a}} + 2{\rm{c}} - 3{\rm{b}}\).
We are given an equation that connects the sides (a, b, c) and angles (A, C) of triangle ABC. To find the relationship between the sides (whether they are in A.P., G.P., or H.P.), we need to simplify this equation. We can use standard trigonometric identities and the Law of Cosines.
Recall the half-angle formula for sine squared: \({\sin ^2}\left( {\frac{x}{2}} \right) = \frac{{1 - \cos x}}{2}\). Applying this to the terms involving angles A and C:
Substitute these into the given equation:
\[2{\rm{a}}\left( {\frac{{1 - \cos C}}{2}} \right) + 2{\rm{c}}\left( {\frac{{1 - \cos A}}{2}} \right) = 2{\rm{a}} + 2{\rm{c}} - 3{\rm{b}}\]
Simplify the equation:
\[{\rm{a}}(1 - \cos C) + {\rm{c}}(1 - \cos A) = 2{\rm{a}} + 2{\rm{c}} - 3{\rm{b}}\]
\[{\rm{a}} - {\rm{a}}\cos C + {\rm{c}} - {\rm{c}}\cos A = 2{\rm{a}} + 2{\rm{c}} - 3{\rm{b}}\]
Rearrange the terms to isolate the \(3b\) term:
\[3{\rm{b}} = 2{\rm{a}} + 2{\rm{c}} - {\rm{a}} + {\rm{a}}\cos C - {\rm{c}} + {\rm{c}}\cos A\]
\[3{\rm{b}} = {\rm{a}} + {\rm{c}} + {\rm{a}}\cos C + {\rm{c}}\cos A\]
Now, we use the Law of Cosines to express \(\cos A\) and \(\cos C\) in terms of the sides a, b, and c:
Substitute these expressions into the equation \(3{\rm{b}} = {\rm{a}} + {\rm{c}} + {\rm{a}}\cos C + {\rm{c}}\cos A\):
\[3{\rm{b}} = {\rm{a}} + {\rm{c}} + {\rm{a}}\left( {\frac{{{a^2} + {b^2} - {c^2}}}{{2ab}}} \right) + {\rm{c}}\left( {\frac{{{b^2} + {c^2} - {a^2}}}{{2bc}}} \right)\]
\[3{\rm{b}} = {\rm{a}} + {\rm{c}} + \frac{{{a^2} + {b^2} - {c^2}}}{{2b}} + \frac{{{b^2} + {c^2} - {\rm{a}}^2}}{{2b}}\]
To eliminate the denominators, multiply the entire equation by \(2b\):
\[3{\rm{b}}(2{\rm{b}}) = ( {\rm{a}} + {\rm{c}} )(2{\rm{b}}) + \left( {\frac{{{a^2} + {b^2} - {c^2}}}{{2b}}} \right)(2b) + \left( {\frac{{{b^2} + {c^2} - {\rm{a}}^2}}{{2b}}} \right)(2b)\]
\[6{{\rm{b}}^2} = 2{\rm{ab}} + 2{\rm{cb}} + {{\rm{a}}^2} + {{\rm{b}}^2} - {{\rm{c}}^2} + {{\rm{b}}^2} + {{\rm{c}}^2} - {{\rm{a}}^2}\]
Combine like terms on the right side. The \(a^2\) and \(-a^2\) terms cancel, and the \(c^2\) and \(-c^2\) terms cancel:
\[6{{\rm{b}}^2} = 2{\rm{ab}} + 2{\rm{cb}} + 2{{\rm{b}}^2}\]
Subtract \(2{{\rm{b}}^2}\) from both sides:
\[6{{\rm{b}}^2} - 2{{\rm{b}}^2} = 2{\rm{ab}} + 2{\rm{cb}}\]
\[4{{\rm{b}}^2} = 2{\rm{b}}({\rm{a}} + {\rm{c}})\]
Since b is a side of a triangle, \(b \neq 0\). We can divide both sides by \(2b\):
\[\frac{{4{{\rm{b}}^2}}}{{2{\rm{b}}}} = \frac{{2{\rm{b}}({\rm{a}} + {\rm{c}})}}{{2{\rm{b}}}}\]
\[2{\rm{b}} = {\rm{a}} + {\rm{c}}\]
The relationship \(2b = a + c\) is the defining condition for three numbers a, b, and c to be in Arithmetic Progression (A.P.). In an A.P., the middle term is the average of the first and third terms, or equivalently, the difference between consecutive terms is constant (\(b - a = c - b\), which simplifies to \(2b = a + c\)).
Thus, the sides a, b, and c of the triangle satisfy the condition for being in Arithmetic Progression.
Starting from the given trigonometric equation involving the sides and angles of triangle ABC, we used half-angle formulas and the Law of Cosines to transform the equation. Through algebraic simplification, we derived the relationship \(2b = a + c\), which proves that the sides of the triangle are in Arithmetic Progression (A.P.).
Understanding different types of progressions is key in sequence and series problems. Here's a quick review:
| Progression Type | Condition for terms \(x, y, z\) | Description |
|---|---|---|
| Arithmetic Progression (A.P.) | \(2y = x + z\) or \(y - x = z - y\) | Each term after the first is obtained by adding a constant difference to the preceding term. |
| Geometric Progression (G.P.) | \(y^2 = xz\) or \(\frac{y}{x} = \frac{z}{y}\) | Each term after the first is obtained by multiplying the preceding term by a constant ratio. |
| Harmonic Progression (H.P.) | \(\frac{2}{y} = \frac{1}{x} + \frac{1}{z}\) or \(\frac{1}{x}, \frac{1}{y}, \frac{1}{z}\) are in A.P. | The reciprocals of the terms are in Arithmetic Progression. |
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