The radius of a circle is 13 cm and the length of one of its chords is 10 cm. What is the distance of the chord from the centre?
12 cm
The perpendicular drawn from the centre of a circle to a chord bisects the chord.
So half of the chord length = 10/2 = 5 cm.
Let d be the distance of the chord from the centre. Using the Pythagorean theorem in the right triangle formed by the radius, half-chord and the perpendicular distance: d^2 + 5^2 = 13^2.
d^2 = 169 - 25 = 144, so d = 12 cm.
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