The product of conductivity and resistivity of a conductor
Is the same for all conductors
Let's explore the relationship between conductivity and resistivity and find their product for a conductor. These are fundamental properties of materials that describe how well they conduct electric current.
Resistivity, often denoted by the Greek letter $\rho$ (rho), is a measure of how strongly a material opposes the flow of electric current. A high resistivity means the material is a poor conductor (an insulator), while a low resistivity means it is a good conductor.
Conductivity, often denoted by the Greek letter $\sigma$ (sigma), is a measure of how well a material conducts electric current. It is the reciprocal of resistivity. A high conductivity means the material is a good conductor, while a low conductivity means it is a poor conductor.
Conductivity ($\sigma$) is defined as the reciprocal of resistivity ($\rho$). This means:
\(\sigma = \frac{1}{\rho}\)
This relationship holds true for all conducting materials under given physical conditions (like temperature). It's a fundamental definition in electromagnetism.
Now, let's find the product of conductivity ($\sigma$) and resistivity ($\rho$).
We have the relationship:
\(\sigma = \frac{1}{\rho}\)
To find the product $\sigma \times \rho$, we can substitute the expression for $\sigma$ into the product:
\(\text{Product} = \sigma \times \rho = \left(\frac{1}{\rho}\right) \times \rho\)
When we multiply $\left(\frac{1}{\rho}\right)$ by $\rho$, the $\rho$ terms cancel out:
\(\text{Product} = \frac{1}{\rho} \times \rho = 1\)
So, the product of conductivity and resistivity is always 1.
Let's look at the given options based on our finding that $\sigma \times \rho = 1$ for any conductor.
Depends on pressure applied
Resistivity and conductivity can be affected by physical conditions like temperature and, to some extent, pressure, but their *product* is a mathematical identity derived from their definition. The product itself does not depend on pressure.
Depends on current flowing through conductor
Resistivity and conductivity are intrinsic material properties (though they can depend on temperature). They do not depend on the current flowing through the conductor. The current is a consequence of the voltage applied and the conductor's resistance (which is related to resistivity, length, and area), not the other way around. Therefore, their product does not depend on the current.
Is the same for all conductors
Since the product of conductivity ($\sigma$) and resistivity ($\rho$) is always 1, i.e., $\sigma \times \rho = 1$, this value is constant and is 1 for *any* conductor (or insulator, for that matter). It does not vary from material to material. This option aligns with our calculation.
Varies from conductor to conductor
This contradicts our finding that the product is always 1, a constant value. While resistivity and conductivity *individually* vary greatly from one material to another (e.g., copper has low resistivity/high conductivity, rubber has high resistivity/low conductivity), their product remains constant at 1.
Based on the analysis, the product of conductivity and resistivity of a conductor is always 1, which means it is the same for all conductors.
The product of the conductivity and resistivity of any material, including a conductor, is always equal to 1. This is a fundamental relationship based on their definitions as reciprocals of each other.
| Concept | Symbol | Definition | Unit |
|---|---|---|---|
| Resistivity | $\rho$ | Opposition to current flow per unit length and area | $\Omega \cdot \text{m}$ |
| Conductivity | $\sigma$ | Ability to conduct current per unit length and area | $\text{S}/\text{m}$ or $(\Omega \cdot \text{m})^{-1}$ |
| Property | Relationship | Product |
|---|---|---|
| Conductivity ($\sigma$) | $\sigma = 1/\rho$ | $\sigma \times \rho = 1$ (Constant for all materials) |
| Resistivity ($\rho$) | $\rho = 1/\sigma$ |
While the product $\sigma \times \rho$ is always 1, the individual values of $\sigma$ and $\rho$ for a material can be influenced by several factors:
Understanding these factors is crucial when working with electrical properties of materials in various applications.
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