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Question

The power taken by a 3-ϕ load is given by the expression

The correct answer is

√3 VLIL cos ϕ

Understanding 3-Phase Load Power

In electrical engineering, understanding the power consumed by a 3-phase load is crucial. A 3-phase system involves three alternating currents that are out of phase with each other. The power consumed by such a load depends on the voltage, current, and the phase difference between them.

Formula for 3-Phase Power

The total active power (P) consumed by a balanced 3-phase load can be calculated using the line voltage ($V_L$), the line current ($I_L$), and the power factor ($\cos \varphi$). The power factor represents the cosine of the angle ($\varphi$) between the voltage and current phasors.

The standard formula for the active power in a 3-phase system, when using line voltage and line current, is:

$$P = \sqrt{3} \times V_L \times I_L \times \cos \varphi$$

Where:

  • $P$ is the active power in Watts (W).
  • $V_L$ is the Line-to-Line voltage in Volts (V).
  • $I_L$ is the Line current in Amperes (A).
  • $\cos \varphi$ is the power factor of the load.

Analyzing the Options

Let's examine the given options in light of the correct formula:

  • Option 1:

    3 $V_L$$I_L$ $\cos \varphi$

    - This formula is typically associated with the sum of powers in a single-phase system or relates differently to line/phase quantities in 3-phase systems depending on context, but it's not the standard expression for total 3-phase power using line values.
  • Option 2:

    $\sqrt{3}$ $V_L$$I_L$ $\cos \varphi$

    - This matches the standard formula for calculating the total active power in a balanced 3-phase load using line voltage and line current.
  • Option 3:

    3 $V_L$$I_L$ $\sin \varphi$

    - This uses the sine of the angle instead of the cosine, which is incorrect for active power calculation.
  • Option 4:

    $\sqrt{3}$ $V_L$$I_L$ $\sin \varphi$

    - This uses the sine term, making it incorrect for active power.

Therefore, the correct expression for the power taken by a 3-phase load using line voltage ($V_L$) and line current ($I_L$) is $\sqrt{3} V_L I_L \cos \varphi$.

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Important Questions from Three Phase Circuits

  1. In a balanced three-phase, star-connected system, the phase difference between phase voltages and their respective line voltages is:

  2. Three equal impedances are first connected in star across a balanced 3 phase supply. If connected in delta across the same supply

  3. A three phase circuit is connected with balanced delta connected load of impedance 100 Ω. If the current in each phase is 5 A, the voltage across each load will be

  4. A load of three impedances each (6 + j9) is supplied through a line having an impedance of (1 + j2) Ω. The supply voltage is 400 V at 50 Hz. Determine input and output powers respectively when the load is star connected.

  5. In a Δ-Δ system, a phase voltage of 100 V produces a line voltage of:

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