A three phase circuit is connected with balanced delta connected load of impedance 100 Ω. If the current in each phase is 5 A, the voltage across each load will be
500 V
To solve this problem, we need to determine the voltage across each load in a balanced delta-connected system. We have the following information:
Impedance (Z) = 100 Ω
Current per phase (Iphase) = 5 A
In a delta-connected system, the voltage across each load (Vphase) can be found using Ohm's Law:
Vphase = Iphase × Z
Substitute the given values into the equation:
Vphase = 5\ A × 100\ \Omega = 500\ V
Therefore, the voltage across each load is 500 V.
Thus, the correct answer is 500 V.
Which of the following is true when there is an unbalanced star connected load in a three-phase system?
Which of the following statements about a star connected three phase system is correct?
Which of the following is a possible cause of an unbalanced load in a three-phase system?
Which of the following is true for a system with an unbalanced load of a three-phase system?
In a balanced three-phase, star-connected system, the phase difference between phase voltages and their respective line voltages is:
Three equal impedances are first connected in star across a balanced 3 phase supply. If connected in delta across the same supply
The power taken by a 3-ϕ load is given by the expression
A load of three impedances each (6 + j9) is supplied through a line having an impedance of (1 + j2) Ω. The supply voltage is 400 V at 50 Hz. Determine input and output powers respectively when the load is star connected.