A three phase circuit is connected with balanced delta connected load of impedance 100 Ω. If the current in each phase is 5 A, the voltage across each load will be
500 V
To solve this problem, we need to determine the voltage across each load in a balanced delta-connected system. We have the following information:
Impedance (Z) = 100 Ω
Current per phase (Iphase) = 5 A
In a delta-connected system, the voltage across each load (Vphase) can be found using Ohm's Law:
Vphase = Iphase × Z
Substitute the given values into the equation:
Vphase = 5\ A × 100\ \Omega = 500\ V
Therefore, the voltage across each load is 500 V.
Thus, the correct answer is 500 V.
The direction of rotation of a three-phase induction motor is determined by its ________.
The real power taken by three-phase load is given by -
A phase sequence indicator rotates clockwise for phase sequence of RYB. If the phase sequence is changed to BRY, it will _______.
If a phase sequence indicator rotates clockwise for a phase sequence of RYB, then what happens when the phase sequence is changed to BRY?
In a star-connected system, the phase angle difference between line and phase voltage is: