Population Calculation After Percentage Increases
This problem involves calculating the final population of a village after two consecutive percentage increases.
Initial Population
The starting population of the village is given as 2,90,000.
Year 1 Population Increase
The population increased by 10% in the first year. To find the population after the first year:
Population after Year 1 = Initial Population $\times (1 + \text{Increase Rate Year 1})$
Population after Year 1 = $2,90,000 \times (1 + \frac{10}{100})$
Population after Year 1 = $2,90,000 \times (1 + 0.10)$
Population after Year 1 = $2,90,000 \times 1.10 = 3,19,000$
Year 2 Population Increase
In the second year, the population increased by 30% based on the population at the end of the first year.
Population after Year 2 = Population after Year 1 $\times (1 + \text{Increase Rate Year 2})$
Population after Year 2 = $3,19,000 \times (1 + \frac{30}{100})$
Population after Year 2 = $3,19,000 \times (1 + 0.30)$
Population after Year 2 = $3,19,000 \times 1.30 = 4,14,700$
Final Population Calculation
The final population of the village after two years is 4,14,700.
Final Answer: The population after two years is 4,14,700.
Important Questions from Percentage (Notes)
In an election between two candidates, a candidate who got $30\%$ of the total votes is defeated by $15000$ votes. The number of votes obtained by the winning candidate is:-
- Which of the following multipliers will increase a given number by 25.3 % ?
If A earns \(33\frac{1}{3}%\) more than B, then how much percent does B earn less than A?
- दो उम्मीदवारों के बीच एक कॉलेज चुनाव में, एक उम्मीदवार को कुल वैध मतों में से $55\%$ वोट मिले । $15\%$ वोट अवैध थे । यदि कुल वोट $15,200$ थे, तो दूसरे उम्मीदवार को कितने वैध वोट मिले ?
- एक शहर की जनसंख्या एक दशक में $1,75,000$ से बढ़कर $2,62,500$ हो गई । प्रति वर्ष जनसंख्या में औसत प्रतिशत वृद्धि है
