If A earns \(33\frac{1}{3}%\) more than B, then how much percent does B earn less than A?
This question asks us to determine the percentage difference in earnings between two people, A and B. Specifically, we know that A earns more than B, and we need to find out by what percentage B earns less than A.
We are given that A earns \(33\frac{1}{3}%\) more than B. Let's understand this statement:
To calculate the actual percentage decrease for B, let's assume a base earning for B. A convenient way to handle percentages is to assume B earns 100 units.
Let B's earnings = \( 100 \text{ units} \).
Since A earns \( \frac{1}{3} \) more than B, the extra amount A earns is:
Extra amount = \( \frac{1}{3} \times \text{B's earnings} = \frac{1}{3} \times 100 = \frac{100}{3} \text{ units} \).
Now, we can find A's total earnings:
A's earnings = B's earnings + Extra amount
A's earnings = \( 100 + \frac{100}{3} = \frac{300}{3} + \frac{100}{3} = \frac{400}{3} \text{ units} \).
The question asks how much B earns less than A. To find this percentage, we first need the difference in their earnings, and then express this difference as a percentage of A's earnings (since A's earnings are the new reference point).
Difference in earnings = A's earnings - B's earnings
Difference = \( \frac{400}{3} - 100 = \frac{400}{3} - \frac{300}{3} = \frac{100}{3} \text{ units} \).
Now, we calculate the percentage decrease relative to A's earnings:
Percentage less = \( \left( \frac{\text{Difference}}{\text{A's earnings}} \right) \times 100% \)
Substituting the values:
Percentage less = \( \left( \frac{100/3}{400/3} \right) \times 100% \)
Simplify the fraction \( \frac{100/3}{400/3} \), which is \( \frac{100}{400} \) or \( \frac{1}{4} \).
Percentage less = \( \frac{1}{4} \times 100% \)
Percentage less = \( 25% \).
A quicker way to solve this is using a standard formula. If one value increases by \( x% \) compared to another, the second value decreases by \( \frac{x}{100+x} \times 100% \) compared to the first.
Here, \( x = 33\frac{1}{3} = \frac{100}{3} \).
Using the formula:
Percentage decrease = \( \frac{100/3}{100 + 100/3} \times 100% \)
Calculate the denominator: \( 100 + \frac{100}{3} = \frac{300+100}{3} = \frac{400}{3} \).
Substitute back into the formula:
Percentage decrease = \( \frac{100/3}{400/3} \times 100% \)
Percentage decrease = \( \frac{100}{400} \times 100% \)
Percentage decrease = \( \frac{1}{4} \times 100% = 25% \).
Both methods confirm that B earns 25% less than A.
In an election between two candidates, a candidate who got $30\%$ of the total votes is defeated by $15000$ votes. The number of votes obtained by the winning candidate is:-