All Exams Test series for 1 year @ ₹349 only
Question

The physical quantity used to describe the rate of change of displacement with time has which of the following dimensional formulae?

This question was previously asked in
UPTET 2026 Paper 2 Social Studies Question Paper (3-Jul-2026) (Shift 1)
The correct answer is

[M⁰LT⁻¹]

The rate of change of displacement with time is velocity. Velocity is defined as displacement divided by time:

\(v = \dfrac{\text{displacement}}{\text{time}}\)

The dimension of displacement (a length) is \([L]\) and the dimension of time is \([T]\), so the dimensional formula of velocity is:

\([v] = \dfrac{[L]}{[T]} = [M^{0}L^{1}T^{-1}]\)

This matches the dimensional formula with no mass dependence, length to the power one, and time to the power minus one.

Was this answer helpful?

Similar Questions

  1. A body of mass 4 kilogram moving at 8 meter/second is brought to rest uniformly in 2 seconds. What is the magnitude of the retarding force applied?

  2. Which of the following is a vector quantity that acts in the same direction as the net force applied on a body?


Important Questions from Motion

  1. The motion of a particle of mass m is described by the relation, y = ut - 1⁄2 gt2, where u is the initial velocity of the particle. The force acting on the particle is

  2. The motion of ______ body is an example of uniformly accelerated motion.

  3. in a particular direction is velocity.
  4. Motion of an object is if its velocity is constant.

  5. The motion of the body moving along a circular path is an example of ______.

Need Expert Advice?
Upcoming Exams
CTET
September 06, 2026
MH SET
September 06, 2026
Test Series
UP TET img
Teaching
UPTET 2026 (Paper 1 & 2) Mock Test Series
257 Tests 16 Tests Free
2125 Attempts
4.6(18)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App