A body of mass 4 kilogram moving at 8 meter/second is brought to rest uniformly in 2 seconds. What is the magnitude of the retarding force applied?
16 N
The initial velocity is \(u = 8 \ m/s\), the final velocity is \(v = 0\), and the time taken is \(t = 2 \ s\).
Using \(a = \frac{v-u}{t}\), the retardation is \(a = \frac{0-8}{2} = -4 \ m/s^2\), so the magnitude of deceleration is \(4 \ m/s^2\).
By Newton's second law, \(F = m \times a = 4 \times 4 = 16 \ N\).
Hence, the magnitude of the retarding force applied is 16 N.
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