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Question

The order n for a given substrate concentration in an enzyme catalyzed reaction following Michaelis-Menten kinetics, is

The correct answer is
$0 \le n \le 1$

Michaelis-Menten Kinetics: Reaction Order Range

The order of an enzyme-catalyzed reaction with respect to substrate concentration ($[S]$) under Michaelis-Menten kinetics is not constant. It depends on the specific substrate concentration ($[S]$) relative to the Michaelis constant ($K_m$).

Order at Low Substrate Concentration

When the substrate concentration is much lower than $K_m$ ($[S] \ll K_m$), the Michaelis-Menten equation simplifies. The rate ($v$) becomes directly proportional to $[S]$:

$v \approx \frac{V_{max}}{K_m}[S]$

In this scenario, the reaction is considered first order with respect to the substrate ($n=1$).

Order at High Substrate Concentration

When the substrate concentration is much higher than $K_m$ ($[S] \gg K_m$), the equation simplifies differently. The rate ($v$) approaches the maximum velocity ($V_{max}$) and becomes independent of $[S]$:

$v \approx V_{max}$

In this scenario, the reaction is considered zero order with respect to the substrate ($n=0$).

Overall Reaction Order

As the substrate concentration ($[S]$) increases from very low levels to very high levels, the reaction order ($n$) transitions from 1 down to 0.

Therefore, for any given substrate concentration in a reaction following Michaelis-Menten kinetics, the order ($n$) must lie within the inclusive range of 0 to 1.

  • Option 1 ($n=1$): Only true when $[S] \ll K_m$.
  • Option 2 ($n=0$): Only true when $[S] \gg K_m$.
  • Option 3 ($n$ is not defined): Incorrect.
  • Option 4 ($0 \le n \le 1$): Correctly represents the possible range for the reaction order.
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Important Questions from Enzyme Kinetics Michaelis Menten K_m V_{max}

  1. An enzyme following Michaelis-Menten kinetics, catalyses a reaction with an initial velocity ($V_0$) of $2\ \mu\text{M s}^{-1}$ at the substrate concentration of $10\ \mu\text{M}$. If the turnover number ($k_{\text{cat}}$) of the enzyme for the given substrate is $500\ \text{s}^{-1}$ and the enzyme concentration in the reaction is $0.01\ \mu\text{M}$, then the value of the Michaelis-Menten constant ($K_m$) would be__________ $\times\ 10^{-6}\ \text{M}$ (in integer).
  2. The graph below shows the activity of enzyme pepsin in the presence of inhibitors aliphatic alcohols (P) or N-acetyl-1-phenylalanine (Q). Which ONE of the following represents the nature of inhibition by P and Q, respectively? 

  3. The following plot represents the Lineweaver-Burk equation of an enzymatic reaction both in the presence and the absence of inhibitor. Here, V is the velocity of reaction and S is the substrate concentration.

    The nature of inhibition shown in the plot is

  4. For an enzyme catalyzed reaction, the plot that correctly represents the relationship between the rate and temperature is
  5. In an enzyme catalyzed reaction, the initial reaction velocity is only one fourth of its maximum velocity. If the substrate concentration is $3.0 \times 10^{-3}$ mM, the value of $K_m$ in micro molar ($\mu$M) will be ....
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