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Question

The numbers in each set are related to each other in a certain way.
(2, 8, 4), (7, 343, 49), (4, 64, ?)
Based on the relationship among the numbers in the first two sets, select the number that can replace the question mark (?) in the third set.

This question was previously asked in
SSC Selection Post 2024 Question Paper (26-Jun-2024) (Shift-4)
The correct answer is
16

Understanding the Number Set Relationship

The question presents three sets of numbers, where the numbers within each set are related in a specific pattern. We need to identify this pattern using the first two sets and then apply it to find the missing number in the third set.

Analyzing the First Set: (2, 8, 4)

Let's denote the numbers in a set as $(a, b, c)$. For the first set (2, 8, 4):

  • The first number ($a$) is 2.
  • The second number ($b$) is 8. We observe that $2^3 = 2 \times 2 \times 2 = 8$.
  • The third number ($c$) is 4. We observe that $2^2 = 2 \times 2 = 4$.

So, the relationship seems to be $(a, a^3, a^2)$.

Analyzing the Second Set: (7, 343, 49)

Let's check if the same relationship $(a, a^3, a^2)$ holds for the second set (7, 343, 49):

  • The first number ($a$) is 7.
  • The second number ($b$) is 343. Let's calculate $7^3$: $7^3 = 7 \times 7 \times 7 = 49 \times 7 = 343$. This matches.
  • The third number ($c$) is 49. Let's calculate $7^2$: $7^2 = 7 \times 7 = 49$. This also matches.

The relationship $(a, a^3, a^2)$ is confirmed for the first two sets.

Applying the Relationship to the Third Set: (4, 64, ?)

Now, we apply the identified pattern $(a, a^3, a^2)$ to the third set (4, 64, ?):

  • The first number ($a$) is 4.
  • The second number ($b$) is 64. Let's verify: $4^3 = 4 \times 4 \times 4 = 16 \times 4 = 64$. This is correct.
  • The third number ($c$) is the unknown value we need to find. According to the pattern, it should be $a^2$.

Calculating the third number:

$c = a^2 = 4^2 = 4 \times 4 = 16$.

Conclusion

Based on the established pattern $(a, a^3, a^2)$, the missing number in the third set (4, 64, ?) is 16.

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