The number of maximum electrons in N shell is
32
Atoms have electrons orbiting the nucleus in specific energy levels or shells. These shells are often designated by letters, starting with K closest to the nucleus, followed by L, M, N, and so on. They can also be represented by a principal quantum number, 'n', where n=1 for the K shell, n=2 for the L shell, n=3 for the M shell, n=4 for the N shell, and so on.
Each electron shell has a maximum capacity for holding electrons. This maximum number of electrons in a shell with principal quantum number 'n' is determined by a simple formula:
\[ \text{Maximum number of electrons} = 2n^2 \]
The question asks for the maximum number of electrons in the N shell. To find this, we first need to identify the principal quantum number 'n' corresponding to the N shell.
Now we can use the formula \(2n^2\) with n = 4 to calculate the maximum capacity of the N shell.
\[ \text{Maximum electrons in N shell} = 2 \times (4)^2 \]
First, calculate \(4^2\):
\[ (4)^2 = 4 \times 4 = 16 \]
Then, multiply the result by 2:
\[ 2 \times 16 = 32 \]
Therefore, the maximum number of electrons that the N shell can hold is 32.
Let's quickly look at the maximum capacity of the first few electron shells using the same formula \(2n^2\):
| Shell | Principal Quantum Number (n) | Maximum Electrons (\(2n^2\)) |
|---|---|---|
| K | 1 | \(2 \times 1^2 = 2\) |
| L | 2 | \(2 \times 2^2 = 8\) |
| M | 3 | \(2 \times 3^2 = 18\) |
| N | 4 | \(2 \times 4^2 = 32\) |
As shown in the table and calculated, the maximum number of electrons in the N shell is 32.
| Electron Shell | Principal Quantum Number (n) | Maximum Electron Capacity |
|---|---|---|
| K | 1 | 2 |
| L | 2 | 8 |
| M | 3 | 18 |
| N | 4 | 32 |
| O | 5 | 50 |
While the formula \(2n^2\) gives the total maximum capacity of a shell, each shell is further divided into subshells (s, p, d, f). Each subshell contains one or more orbitals, and each orbital can hold a maximum of two electrons.
The number of subshells within a shell 'n' is equal to 'n'. The types of subshells present in shell 'n' are s, p, d, ..., up to a subshell type corresponding to the azimuthal quantum number l = n-1.
This subshell structure explains how the total capacity \(2n^2\) is achieved by adding up the capacities of the individual subshells within that main shell.
When one strikes a safety match, the first step is
March List-I with List-II and select the correct answer using the code given below the Lists:
List I (Element) | List II (Highest Valency) |
A. Sulfur | 1. Five |
B. Phosphorous | 2. Six |
C. Lead | 3. Two |
D. Silver | 4. Four |
Match List I with List II and select the answer using the code given below the Lists:
| List I (Element) | List II (Atomicity) |
| A. Phosphorus | 1. 2 |
| B. Nitrogen | 2. 1 |
| C. Neon | 3. 8 |
| D. Sulphur | 4. 4 |
Code:
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