The given reaction involves the reaction of ethyl acetoacetate with benzaldehyde and ammonia in ethanol at pH 8.5. This is a classic example of the Knoevenagel condensation, followed by cyclization involving ammonia, which typically yields a heterocyclic compound.

Here is a step-by-step breakdown of the reaction:

1. Knoevenagel Condensation:
   • The reaction begins with the condensation of benzaldehyde with one equivalent of ethyl acetoacetate. Under basic conditions, the active methylene group of ethyl acetoacetate is deprotonated, which then attacks the carbonyl carbon of benzaldehyde.
   • This step forms an intermediate alkene through the Knoevenagel condensation.
2. Ammonia Reaction:
   • Ammonia acts as a nucleophile that can attack the electrophilic sites formed after condensation. This promotes further reaction leading towards ring formation.
3. Cyclization:
   • The reaction proceeds through cyclization, leading to the formation of a heterocyclic compound. In this scenario, given the reagents, it is likely to be a quinoline derivative.

The major product corresponds to the compound is

Conclusion: The correct major product formed in this reaction is a quinoline derivative, typically formed through a sequence of condensation and cyclization steps in slightly basic conditions.