The magnetic force on a charged particle moving parallel to a uniform magnetic field is:
Zero
The magnetic force experienced by a charged particle is given by \(\vec{F} = q\vec{v} \times \vec{B}\), whose magnitude is \(F = qvB\sin\theta\), where \(\theta\) is the angle between the velocity \(\vec{v}\) and the field \(\vec{B}\).
When the particle moves parallel to the field, \(\theta = 0^\circ\), and \(\sin 0^\circ = 0\). Substituting this gives \(F = qvB\sin 0^\circ = 0\).
So a charged particle moving exactly along the direction of a uniform magnetic field experiences no magnetic force at all, and continues moving in a straight line at constant speed.
Similar Questions
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Important Questions from Magnetism
What is the direction of magnetic field lines outside a magnet?
Which of the following statement is correct?
।. Magnetic field has both magnitude and direction.
II. The magnetic field inside a current-carrying straight long solenoid is the same at all points.
The magnetic effect of electric current was discovered by _____.
The important property of magnet which was exploited by navigators and travelers from the ancient times is:
The magnet used to lift and transport heavy loads like big metals, steel girders and scrap iron objects for loading and unloading purposes is known as____.
