The magnetic force on a charged particle moving parallel to a uniform magnetic field is:
Zero
The magnetic force experienced by a charged particle is given by \(\vec{F} = q\vec{v} \times \vec{B}\), whose magnitude is \(F = qvB\sin\theta\), where \(\theta\) is the angle between the velocity \(\vec{v}\) and the field \(\vec{B}\).
When the particle moves parallel to the field, \(\theta = 0^\circ\), and \(\sin 0^\circ = 0\). Substituting this gives \(F = qvB\sin 0^\circ = 0\).
So a charged particle moving exactly along the direction of a uniform magnetic field experiences no magnetic force at all, and continues moving in a straight line at constant speed.
Similar Questions
At the magnetic equator of the Earth, what is the value of the angle of dip?
A substance that is weakly attracted when placed in an external magnetic field and does not retain magnetization after the field is removed is classified as :
Important Questions from Magnetism
How many of the following materials can be attracted by a magnet?
1. Plastic
2. Carbon
3. Aluminium
4. Stainless Steel
Select the correct answer using the code given below:
What will happen if a collection of positive and negative charges are passed at a high speed through a magnetic field which is perpendicular to the direction of motion of the charges? (Assume that both kind of charges are NOT going to recombine)
Which scientist suggested that the magnet must also exert an equal and opposite force on the current-carrying conductor?
Paramagnetic substances are-
The magnetic field lines produced inside a long current-carrying solenoid is similar to that of a:
