This solution determines the minimum length of a DNA sequence segment that is statistically unique within a large genome (3 billion base pairs).
DNA uses 4 bases (A, T, C, G). A sequence of length $L$ can have $4^L$ different combinations.
In a genome of size $N = 3 \times 10^9$ base pairs, the expected number of times a specific sequence of length $L$ appears is approximately $N / 4^L$. For a sequence to be considered unique, this value should ideally be less than 1.
Setting the condition for uniqueness:
$ \frac{N}{4^L} < 1 $
$ 4^L > N $
We need to find the smallest integer $L$ such that $4^L > 3 \times 10^9$.
Taking logarithm base 4:
$ L > \log_4(3 \times 10^9) $
Using base 10 logarithms for calculation:
$ L > \frac{\log_{10}(3 \times 10^9)}{\log_{10}(4)} $
$ L > \frac{\log_{10}(3) + 9}{\log_{10}(4)} $
Using approximations $\log_{10}(3) \approx 0.477$ and $\log_{10}(4) \approx 0.602$:
$ L > \frac{0.477 + 9}{0.602} \approx \frac{9.477}{0.602} \approx 15.74 $
Since $L$ must be an integer and $L > 15.74$, the smallest integer value for $L$ is 16.
Let's verify:
Therefore, the minimum unique sequence length is 16 base pairs.
Consider the following multiple sequence alignment of four DNA sequences.
$\begin{matrix}A & C & T & A \\ A & C & T & G \\ A & G & T & C \\ A & G & C & T \end{matrix} $
Shannon's entropy of the above alignment is ________.
The transcription factor X binds a 10 base pair DNA stretch. In the DNA of an organism, X was found to bind at 20 distinct sites. An analysis of these 20 binding sites showed the following distribution:
| Base | Position in the binding site | |||||||||
| 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | |
| A | 11 | 0 | 0 | 0 | 16 | 2 | 4 | 0 | 4 | 3 |
| T | 3 | 0 | 19 | 0 | 1 | 3 | 4 | 20 | 2 | 4 |
| G | 4 | 20 | 0 | 0 | 2 | 4 | 6 | 0 | 12 | 2 |
| C | 2 | 0 | 1 | 20 | 1 | 11 | 6 | 0 | 2 | 11 |
What is the consensus sequence for the binding site of X?