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Question

The largest side of the triangle is 3 times of it's shortest side. The length of the third side is 2 cm more than shortest side. If the perimeter of the triangle is 27 cm, then find the length of the shortest side.

The correct answer is
5 cm

Finding the Shortest Side of a Triangle Using Perimeter

This problem involves finding the length of the shortest side of a triangle when we know the relationships between its sides and its total perimeter.

Understanding the Triangle's Sides

Let's denote the length of the shortest side of the triangle as s.

  • The length of the largest side is 3 times the shortest side, so its length is $3s$.
  • The length of the third side is 2 cm more than the shortest side, so its length is $s + 2$ cm.

Using the Perimeter Information

The perimeter of a triangle is the sum of the lengths of all its sides.

We are given that the perimeter is 27 cm.

Therefore, we can write the equation:

Shortest side + Third side + Largest side = Perimeter

Substituting the expressions for the sides:

$ s + (s + 2) + 3s = 27 $

Step-by-Step Calculation

  1. Combine like terms: Add all the terms involving s. $ (s + s + 3s) + 2 = 27 $ $ 5s + 2 = 27 $
  2. Isolate the term with s: Subtract 2 from both sides of the equation. $ 5s = 27 - 2 $ $ 5s = 25 $
  3. Solve for s: Divide both sides by 5 to find the length of the shortest side. $ s = \frac{25}{5} $ $ s = 5 $

Verifying the Solution

If the shortest side ($s$) is 5 cm:

  • The third side is $s + 2 = 5 + 2 = 7$ cm.
  • The largest side is $3s = 3 \times 5 = 15$ cm.

The perimeter is $5 \text{ cm} + 7 \text{ cm} + 15 \text{ cm} = 27 \text{ cm}$. This matches the given perimeter.

Conclusion

The length of the shortest side of the triangle is 5 cm.

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Important Questions from Algebra (Notes)

  1. If $(y-12) = 4\sqrt{5}$, then find the value of $\sqrt{y-3} - \frac{1}{\sqrt{y-3}}$.
  2. A square matrix having all the elements above the leading diagonal equal to zero is known as:
  3. If $(\frac{7}{11})^{k-5} = (\frac{11}{7})^{k-9}$, find the value of $2^k$.
  4. The sum of the age of A and 5 times the age of B is 36 years. When 3 times the age of A is added to 7 times the age of B, the result is 62 years. The sum of the ages (in years) of A and B is:
  5. 18 bags and 3 pens together cost ₹1,164, whereas 14 bags and 2 pens together cost ₹922. The cost of 9 bags exceeds the cost of 2 pens by:
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