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Question

The sum of the age of A and 5 times the age of B is 36 years. When 3 times the age of A is added to 7 times the age of B, the result is 62 years. The sum of the ages (in years) of A and B is:

The correct answer is
13

Understanding the Age Problem

This problem asks us to find the sum of the ages of two people, A and B. We are given two pieces of information that relate their ages, which we can translate into mathematical equations. This is a classic example of solving a system of linear equations.

Setting Up the Equations

Let the age of person A be represented by the variable $A$, and the age of person B be represented by the variable $B$.

  • The first statement says: "The sum of the age of A and 5 times the age of B is 36 years." This can be written as the equation:

    $A + 5B = 36 \quad (Equation \, 1)$

  • The second statement says: "When 3 times the age of A is added to 7 times the age of B, the result is 62 years." This can be written as the equation:

    $3A + 7B = 62 \quad (Equation \, 2)$

Solving the System of Equations

We now have a system of two linear equations with two variables:

  1. $A + 5B = 36$

  2. $3A + 7B = 62$

We can solve this system using the elimination method. The goal is to eliminate one variable ($A$ or $B$) by manipulating the equations.

  1. Multiply Equation 1 by 3 to make the coefficient of $A$ the same as in Equation 2:

    $3 \times (A + 5B) = 3 \times 36$

    $3A + 15B = 108 \quad (Equation \, 3)$

  2. Subtract Equation 2 from Equation 3 to eliminate $A$:

    $(3A + 15B) - (3A + 7B) = 108 - 62$

    $3A + 15B - 3A - 7B = 46$

    $8B = 46$

  3. Solve for $B$:

    $B = \frac{46}{8}$

    $B = \frac{23}{4}$

    $B = 5.75$

  4. Substitute the value of $B$ back into Equation 1 to find $A$:

    $A + 5 \left( \frac{23}{4} \right) = 36$

    $A + \frac{115}{4} = 36$

  5. Solve for $A$:

    $A = 36 - \frac{115}{4}$

    $A = \frac{36 \times 4}{4} - \frac{115}{4}$

    $A = \frac{144}{4} - \frac{115}{4}$

    $A = \frac{144 - 115}{4}$

    $A = \frac{29}{4}$

    $A = 7.25$

Calculating the Sum of Ages

The question asks for the sum of the ages of A and B, which is $A + B$.

  • $A + B = \frac{29}{4} + \frac{23}{4}$
  • $A + B = \frac{29 + 23}{4}$
  • $A + B = \frac{52}{4}$
  • $A + B = 13$

So, the sum of the ages of A and B is 13 years.

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Important Questions from Algebra (Notes)

  1. If $(y-12) = 4\sqrt{5}$, then find the value of $\sqrt{y-3} - \frac{1}{\sqrt{y-3}}$.
  2. If $x^2 + \frac{1}{x^2} = 16$ and $x \neq 0$, then what is the value of $x^4 + \frac{1}{x^4}$?
  3. In the expansion of (x + 9)(x - 6)(x + 5), what is the coefficient of x?
  4. Find the value of $\frac{x+3}{x^2-2x} \times \frac{2x-1}{x^2+2x+4} \times \frac{x^4-8x}{2x^2+5x-3}$
  5. The roots of the equation $ax^3-24x^2+188x-480=0$ are three consecutive even natural numbers. The value of a is _____.
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