This problem involves finding the costs of individual items (bags and pens) based on the total cost of different combinations. We need to determine the cost of 9 bags and compare it to the cost of 2 pens.
Let's define the variables:
From the information given in the question, we can set up a system of two linear equations:
\( 18b + 3p = 1164 \)
\( 14b + 2p = 922 \)
To solve for \( b \) and \( p \), we can simplify the equations first. Divide Equation 1 by 3 and Equation 2 by 2:
Now we can solve this simpler system. Let's use the elimination method. Subtract Equation 3 from Equation 4:
\( (7b + p) - (6b + p) = 461 - 388 \)
\( 7b + p - 6b - p = 73 \)
\( b = 73 \)
So, the cost of one bag ( \( b \) ) is ₹73.
Now, substitute the value of \( b \) back into Equation 3 to find \( p \):
\( 6b + p = 388 \)
\( 6(73) + p = 388 \)
\( 438 + p = 388 \)
\( p = 388 - 438 \)
\( p = -50 \)
The cost of one pen ( \( p \) ) is ₹-50. While a negative cost is unusual in a real-world scenario, we proceed with this value based on the given equations.
The question asks for the difference between the cost of 9 bags and the cost of 2 pens. This can be represented as \( 9b - 2p \).
Using the values we found for \( b \) and \( p \):
Calculate the values:
Now find the difference \( 9b - 2p \):
\( 9b - 2p = 657 - (-100) \)
\( 9b - 2p = 657 + 100 \)
\( 9b - 2p = 757 \)
The cost of 9 bags exceeds the cost of 2 pens by ₹757.