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Question

A square matrix having all the elements above the leading diagonal equal to zero is known as:

The correct answer is
Lower Triangular Matrix

Understanding Square Matrices with Zeros Above the Leading Diagonal

The question asks to identify the type of square matrix where all the elements situated above the main diagonal are equal to zero. Let's break down the concepts involved:

Matrix Basics

  • Square Matrix: A matrix that has an equal number of rows and columns. For example, a 3x3 matrix has 3 rows and 3 columns.
  • Leading Diagonal (Main Diagonal): This diagonal runs from the top-left corner to the bottom-right corner of a square matrix. The elements on this diagonal have the same row and column index, denoted as $a_{ii}$.
  • Elements Above the Leading Diagonal: These are the elements $a_{ij}$ where the row index $i$ is less than the column index $j$ (i.e., $i < j$).
  • Elements Below the Leading Diagonal: These are the elements $a_{ij}$ where the row index $i$ is greater than the column index $j$ (i.e., $i > j$).

Types of Triangular Matrices

Matrices can be classified based on the location of their non-zero elements relative to the leading diagonal. Two specific types are:

1. Upper Triangular Matrix

An upper triangular matrix is a square matrix where all the elements *below* the leading diagonal are zero. Mathematically, for a matrix $A$, $a_{ij} = 0$ for all $i > j$. Example:

$ A = \begin{pmatrix} a_{11} & a_{12} & a_{13} \\ 0 & a_{22} & a_{23} \\ 0 & 0 & a_{33} \end{pmatrix} $

2. Lower Triangular Matrix

A lower triangular matrix is a square matrix where all the elements *above* the leading diagonal are zero. Mathematically, for a matrix $A$, $a_{ij} = 0$ for all $i < j$. Example:

$ A = \begin{pmatrix} a_{11} & 0 & 0 \\ a_{21} & a_{22} & 0 \\ a_{31} & a_{32} & a_{33} \end{pmatrix} $

Analyzing the Question

The question specifically states that the square matrix has "all the elements *above* the leading diagonal equal to zero".

  • This condition directly matches the definition of a Lower Triangular Matrix, where $a_{ij} = 0$ for $i < j$.
  • Conversely, if the elements *below* the leading diagonal were zero ($a_{ij} = 0$ for $i > j$), it would be an Upper Triangular Matrix.
  • A Null Matrix or Zero Matrix has all elements equal to zero, which is a specific case of both upper and lower triangular matrices but doesn't fit the precise definition given related to the diagonal.

Therefore, a square matrix having all elements above the leading diagonal equal to zero is known as a Lower Triangular Matrix.

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Important Questions from Algebra (Notes)

  1. What is the remainder when 2023²⁰²⁴ + 2025²⁰²⁴ is divided by 2024?
  2. In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If she/he attempts all 60 questions and secures 130 marks, the number of questions she/he attempts wrongly, are?

  3. Match List-I with List-II
     

    List-1List-II
    (A) If $\begin{bmatrix}\lambda-1 & 0 \\  0 & \lambda-1 \end{bmatrix} $, then $\lambda$ is(I) 0
    (B) If A=$ \begin{bmatrix}1 & 2 \\2 & 4 \end{bmatrix} $, then $\Delta$ is(II) 1
    (C) If A = $ \begin{bmatrix}1 & 0 \\0 &  \frac{1}{2}  \end{bmatrix} $, then $|A^{-1}|$ is(III) -2
    (D) If $ \begin{bmatrix}a+1 & 1 \\1 & 2 \end{bmatrix} =  \begin{bmatrix}-1 & 1 \\1 & 2 \end{bmatrix} $, then a is(IV) 2

    Choose the correct answer from the options given below:

  4. If (x - 1) is a factor of $2x^2 - 5x + k = 0$, then the value of k is:
  5. If $x = (2+\sqrt{3})^{\frac{1}{3}} + (2+\sqrt{3})^{-\frac{1}{3}}$ and $x^3-3x + k = 0$, then the value of k is:
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