The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its
Momentum
The question asks about the relationship between the impulse on a particle and its state of motion during a given time interval. Specifically, it asks what quantity the impulse is equal to the change in.
Impulse is a term used in physics that describes the change in momentum of an object when a force is applied to it over a period of time. Mathematically, impulse (\(\vec{J}\)) is defined as the integral of a force (\(\vec{F}\)) over the time interval (\(\Delta t\)) it acts:
\(\vec{J} = \int_{t_1}^{t_2} \vec{F} \, dt\)
If the force is constant over the time interval, the formula simplifies to:
\(\vec{J} = \vec{F} \Delta t\)
Impulse is a vector quantity, meaning it has both magnitude and direction. Its direction is the same as the direction of the force.
One of the fundamental principles in mechanics is the impulse-momentum theorem. This theorem states that the impulse applied to an object is equal to the change in its momentum.
Momentum (\(\vec{p}\)) is defined as the product of an object's mass (\(m\)) and its velocity (\(\vec{v}\)):
\(\vec{p} = m\vec{v}\)
The change in momentum (\(\Delta \vec{p}\)) is the final momentum minus the initial momentum:
\(\Delta \vec{p} = \vec{p}_{\text{final}} - \vec{p}_{\text{initial}} = m\vec{v}_{\text{final}} - m\vec{v}_{\text{initial}}\)
The impulse-momentum theorem can be derived from Newton's second law of motion (\(\vec{F} = m\vec{a} = m \frac{d\vec{v}}{dt} = \frac{d(m\vec{v})}{dt} = \frac{d\vec{p}}{dt}\)), by integrating force with respect to time:
\(\int_{t_1}^{t_2} \vec{F} \, dt = \int_{t_1}^{t_2} \frac{d\vec{p}}{dt} \, dt = [\vec{p}]_{t_1}^{t_2} = \vec{p}(t_2) - \vec{p}(t_1)\)
So, we have:
\(\vec{J} = \Delta \vec{p}\)
This equation directly tells us that the impulse on a particle is equal to the change in its momentum during the time the force acts.
Let's examine the given options in light of the impulse-momentum theorem:
Based on the impulse-momentum theorem, the impulse acting on a particle is equal to the change in its momentum.
The impulse on a particle due to a force acting on it during a given time interval is equal to the change in its momentum. This is a direct consequence of Newton's second law of motion and is formally stated as the impulse-momentum theorem.
| Concept | Definition/Formula | Relationship with Impulse |
|---|---|---|
| Impulse (\(\vec{J}\)) | \(\int \vec{F} \, dt\) or \(\vec{F}\Delta t\) (constant F) | The impulse itself |
| Momentum (\(\vec{p}\)) | \(m\vec{v}\) | Impulse equals the change in momentum (\(\Delta \vec{p}\)) |
| Force (\(\vec{F}\)) | \(m\vec{a}\) or \(d\vec{p}/dt\) | Impulse is the integral of force over time |
| Work Done (\(W\)) | \(\int \vec{F} \cdot d\vec{r}\) or \(\vec{F} \cdot \Delta \vec{r}\) (constant F) | Related to change in kinetic energy, not impulse |
| Energy (\(E\)) | Various forms (Kinetic, Potential, etc.) | Total mechanical energy change is related to work done by non-conservative forces; not directly equal to impulse. |
| Term | Symbol | Definition | Units | Relationship |
|---|---|---|---|---|
| Force | \(\vec{F}\) | Push or pull; causes acceleration | Newtons (N) | Impulse = \(\int \vec{F} \, dt\) |
| Time Interval | \(\Delta t\) | Duration over which force acts | Seconds (s) | Impulse = \(\vec{F}\Delta t\) (constant F) |
| Impulse | \(\vec{J}\) | Effect of force over time | Newton-seconds (N·s) or kg·m/s | \(\vec{J} = \Delta \vec{p}\) |
| Momentum | \(\vec{p}\) | Mass in motion (\(m\vec{v}\)) | kg·m/s or N·s | Change in momentum (\(\Delta \vec{p}\)) = \(\vec{J}\) |
| Change in Momentum | \(\Delta \vec{p}\) | \(\vec{p}_{\text{final}} - \vec{p}_{\text{initial}}\) | kg·m/s or N·s | \(\Delta \vec{p} = \vec{J}\) |
The impulse-momentum theorem is closely related to the principle of conservation of momentum. If the net external force acting on a system is zero (i.e., the net impulse is zero), then the total momentum of the system remains constant.
Consider a system of particles. The total momentum of the system is the vector sum of the momenta of individual particles:
\(\vec{P}_{\text{total}} = \sum \vec{p}_i\)
If \(\vec{F}_{\text{net, external}} = 0\), then the total impulse on the system is zero:
\(\vec{J}_{\text{total}} = \int \vec{F}_{\text{net, external}} \, dt = 0\)
According to the impulse-momentum theorem applied to the system:
\(\vec{J}_{\text{total}} = \Delta \vec{P}_{\text{total}}\)
So, if \(\vec{J}_{\text{total}} = 0\), then \(\Delta \vec{P}_{\text{total}} = 0\), which means the total momentum does not change. This is the principle of conservation of total momentum.
This principle is particularly useful in analyzing collisions and explosions where external forces are negligible compared to internal forces between the particles.
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