The highest four-digit number which is divisible by each of the numbers 16, 36, 45, 48 is
9360
The problem asks us to find the largest four-digit number that is perfectly divisible by several given numbers: 16, 36, 45, and 48. A number that is divisible by each of these numbers must be a multiple of their Least Common Multiple (LCM).
To find the LCM of 16, 36, 45, and 48, we first find the prime factorization of each number.
Now, we list all prime factors that appear in any of the factorizations and take the highest power of each factor:
The LCM is the product of these highest powers:
\(\text{LCM(16, 36, 45, 48)} = \text{2}^4 \times \text{3}^2 \times \text{5}^1 = \text{16} \times \text{9} \times \text{5}\)
\(\text{LCM} = \text{144} \times \text{5} = \text{720}\)
So, any number divisible by 16, 36, 45, and 48 must be a multiple of 720.
We are looking for the largest four-digit number that is a multiple of 720. The largest four-digit number is 9999.
We need to find the largest multiple of 720 that is less than or equal to 9999. We can do this by dividing 9999 by 720.
\(\text{9999} \div \text{720}\)
Using division:
| \(\text{13}\) |
| \(\text{720}\overline{\text{)9999}}\) |
| \(\text{-720}}\) |
| \(\text{---}}\) |
| \(\text{2799}}\) |
| \(\text{-2160}}\) |
| \(\text{----}}\) |
| \(\text{639}}\) |
The division gives a quotient of 13 and a remainder of 639.
This means \(9999 = 720 \times 13 + 639\).
The largest multiple of 720 less than or equal to 9999 is found by multiplying the quotient by the LCM:
\(\text{Largest multiple} = \text{720} \times \text{13}\)
\(\text{720} \times \text{13} = \text{9360}\)
The number 9360 is a four-digit number. The next multiple of 720 would be \(720 \times 14 = 9360 + 720 = 10080\), which is a five-digit number.
Therefore, the highest four-digit number that is divisible by 16, 36, 45, and 48 is 9360.
| Concept | Description | Relevance to Problem |
|---|---|---|
| Divisibility | A number 'a' is divisible by 'b' if dividing 'a' by 'b' leaves no remainder. | We need a number divisible by 16, 36, 45, and 48. |
| Prime Factorization | Breaking down a number into its prime number components multiplied together. | Essential step for finding the LCM. |
| Least Common Multiple (LCM) | The smallest positive integer that is a multiple of two or more numbers. | A number divisible by 16, 36, 45, 48 must be a multiple of their LCM. |
| Highest Four-Digit Number | The largest integer between 1000 and 9999, which is 9999. | Sets the upper limit for our search. |
When you need to find the largest multiple of a number 'N' that is less than or equal to another number 'M', you can follow these steps:
In our case, M = 9999 and N = 720. We found Q = 13 and R = 639. So, the largest multiple of 720 less than or equal to 9999 is \(720 \times 13 = 9360\). Another way to think about it is to subtract the remainder from the largest number: \(9999 - 639 = 9360\).
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select the correct answer using the code given below: