The problem asks for the median beak size given a frequency distribution with specific properties: it is symmetric but not normally distributed. We are provided with the mean value, standard deviation, and kurtosis.
A key property of any symmetric distribution is that its measures of central tendency coincide. This means the mean, median, and mode are equal.
In a symmetric distribution, Median = Mean.
The question explicitly states the frequency distribution of beak sizes is symmetric.
Because the distribution is symmetric, the median must be equal to the mean.
While the standard deviation ($\sigma$ = 25 mm) and kurtosis (10) provide information about the spread and shape (peakedness/tailedness) of the distribution, they do not alter the relationship between the mean and median in a symmetric distribution. The fact that it's not normally distributed is also secondary to the property of symmetry.
Based on the symmetry of the distribution, the median beak size is equal to the given mean beak size.
This value falls within the range suggested by the correct answer (5.9 to 6.1 mm).

The above frequency chart shows the frequency distribution of marks obtained by a set of students in an exam. From the data presented above, which one of the following is CORRECT?