The problem asks us to find the value of '$b$' given a dataset $\{-5, 1, a, 5, b\}$, its ascending order property, and its mean and median values.
The dataset has 5 elements. The median is the middle element in the sorted dataset. In this case, the middle element is '$a$'.
Given that the median is 3, we can set '$a$' equal to 3:
$a = 3$This value of $a=3$ satisfies the condition $1 \le a \le 5$, derived from the ascending order property.
The mean of a dataset is the sum of its elements divided by the number of elements.
The formula for the mean is:
$ \text{Mean} = \frac{\sum \text{elements}}{\text{Number of elements}} $Substitute the given values:
$ \text{Mean} = \frac{-5 + 1 + a + 5 + b}{5} $We are given that the mean is 3. Substitute $a=3$ into the equation:
$ 3 = \frac{-5 + 1 + 3 + 5 + b}{5} $Simplify the numerator:
$ 3 = \frac{4 + b}{5} $To solve for '$b$', multiply both sides by 5:
$ 3 \times 5 = 4 + b $ $ 15 = 4 + b $Isolate '$b$' by subtracting 4 from both sides:
$ b = 15 - 4 $ $ b = 11 $The calculated value is $b=11$. Let's check if this fits all conditions:
The value $b=11$ satisfies all the conditions of the problem.

The above frequency chart shows the frequency distribution of marks obtained by a set of students in an exam. From the data presented above, which one of the following is CORRECT?