The problem states that the cost price (CP) of 48 books is equal to the selling price (SP) of 36 books. We need to find the profit percentage.
Let the cost price of one book be $C$ and the selling price of one book be $S$. According to the question:
Cost Price of 48 books = Selling Price of 36 books
This can be written as:
$48 \times C = 36 \times S$
To find the relationship between $S$ and $C$, we rearrange the equation:
$\frac{S}{C} = \frac{48}{36}$
Simplify the fraction:
$\frac{S}{C} = \frac{4}{3}$
This ratio means that for every $3$ units of cost price, the selling price is $4$ units.
Profit is defined as Selling Price minus Cost Price ($S - C$). The profit percentage is calculated using the formula:
$\text{Profit Percentage} = \frac{\text{Profit}}{\text{Cost Price}} \times 100\%$
$\text{Profit Percentage} = \frac{S - C}{C} \times 100\%$
Substitute the ratio $\frac{S}{C} = \frac{4}{3}$ into the formula:
$\text{Profit Percentage} = \left( \frac{S}{C} - \frac{C}{C} \right) \times 100\%$
$\text{Profit Percentage} = \left( \frac{4}{3} - 1 \right) \times 100\%$
$\text{Profit Percentage} = \left( \frac{4}{3} - \frac{3}{3} \right) \times 100\%$
$\text{Profit Percentage} = \frac{1}{3} \times 100\%$
$\text{Profit Percentage} = 33.333...\%$
Rounding the result to two decimal places, the profit percentage is $33.33\%$.
In an election between two candidates, a candidate who got $30\%$ of the total votes is defeated by $15000$ votes. The number of votes obtained by the winning candidate is:-
If A earns \(33\frac{1}{3}%\) more than B, then how much percent does B earn less than A?