All Exams Test series for 1 year @ ₹349 only
Question

The correlation coefficient between two variables X and Y is found to be 0.6. All the observations on X and Y are transformed using the transformations U = 2 – 3X and V = 4Y + 1. The correlation coefficient between the transformed variables U and V will be

This question was previously asked in
NDA II 2015 GAT Previous Year Paper (16-Dec-2015)
The correct answer is

-0.6

Understanding Correlation Coefficient and Linear Transformations

The question asks how the correlation coefficient between two variables, X and Y, changes when both variables undergo specific linear transformations. We are given the initial correlation coefficient between X and Y, and the equations for the transformations.

The correlation coefficient, denoted by \(r_{XY}\), measures the strength and direction of the linear relationship between two variables X and Y. Its value ranges from -1 to +1.

We are given that the correlation coefficient between X and Y is \(r_{XY} = 0.6\).

The transformations are given as:

  • \(U = 2 - 3X\)
  • \(V = 4Y + 1\)

These are linear transformations. A linear transformation of a variable X is of the form \(U = a + bX\), where 'a' and 'b' are constants. In our case for variable X, \(a=2\) and \(b=-3\). For variable Y, the transformation is \(V = c + dY\), where \(c=1\) and \(d=4\).

Effect of Linear Transformations on Correlation Coefficient

Let's examine how these transformations affect the covariance and standard deviations, which are components of the correlation coefficient formula. The correlation coefficient between U and V is given by:

\(r_{UV} = \frac{Cov(U, V)}{\sigma_U \sigma_V}\)

Where \(Cov(U, V)\) is the covariance between U and V, \(\sigma_U\) is the standard deviation of U, and \(\sigma_V\) is the standard deviation of V.

For linear transformations \(U = a + bX\) and \(V = c + dY\):

The covariance between U and V is related to the covariance between X and Y by:

\(Cov(U, V) = Cov(a + bX, c + dY)\)

Using the properties of covariance, \(Cov(a_1 + b_1X_1, a_2 + b_2X_2) = b_1 b_2 Cov(X_1, X_2)\), we get:

\(Cov(U, V) = (b)(d) Cov(X, Y)\)

In our case, \(b = -3\) and \(d = 4\), so:

\(Cov(U, V) = (-3)(4) Cov(X, Y) = -12 Cov(X, Y)\)

The standard deviation of U is related to the standard deviation of X by:

\(\sigma_U = \sqrt{Var(U)} = \sqrt{Var(a + bX)}\)

Using the property \(Var(a + bX) = b^2 Var(X)\), we get:

\(\sigma_U = \sqrt{b^2 Var(X)} = |b| \sqrt{Var(X)} = |b| \sigma_X\)

In our case, \(b = -3\), so \(\sigma_U = |-3| \sigma_X = 3 \sigma_X\).

Similarly, the standard deviation of V is related to the standard deviation of Y by:

\(\sigma_V = \sqrt{Var(V)} = \sqrt{Var(c + dY)}\)

\(\sigma_V = \sqrt{d^2 Var(Y)} = |d| \sqrt{Var(Y)} = |d| \sigma_Y\)

In our case, \(d = 4\), so \(\sigma_V = |4| \sigma_Y = 4 \sigma_Y\).

Calculating the New Correlation Coefficient

Now substitute these into the formula for \(r_{UV}\):

\(r_{UV} = \frac{Cov(U, V)}{\sigma_U \sigma_V} = \frac{(b)(d) Cov(X, Y)}{|b| \sigma_X |d| \sigma_Y}\)

\(r_{UV} = \frac{(bd)}{|bd|} \frac{Cov(X, Y)}{\sigma_X \sigma_Y}\)

We know that \(r_{XY} = \frac{Cov(X, Y)}{\sigma_X \sigma_Y}\), so:

\(r_{UV} = \frac{(bd)}{|bd|} r_{XY}\)

The term \(\frac{(bd)}{|bd|}\) is equal to +1 if b and d have the same sign, and -1 if b and d have opposite signs. In this problem, \(b = -3\) (negative) and \(d = 4\) (positive). Since they have opposite signs, \(\frac{(bd)}{|bd|} = -1\).

Therefore, \(r_{UV} = -r_{XY}\).

Given \(r_{XY} = 0.6\), the correlation coefficient between U and V is:

\(r_{UV} = -(0.6) = -0.6\)

The correlation coefficient between the transformed variables U and V is -0.6.

This result shows that while scaling and shifting variables linearly does not change the magnitude of the correlation coefficient (it remains 0.6), it can change its sign if the scaling factors (the 'b' and 'd' values) have opposite signs.

Revision Table: Correlation Transformation Summary

Original Variables Transformed Variables Transformation Type Effect on Correlation Coefficient
X, Y \(U = a + bX\) Linear (shift and scale) Correlation with other variables changes based on 'b'.
X, Y \(V = c + dY\) Linear (shift and scale) Correlation with other variables changes based on 'd'.
X, Y (with \(r_{XY}\)) \(U = a + bX\), \(V = c + dY\) Linear (both variables) \(r_{UV} = \frac{(bd)}{|bd|} r_{XY}\). The sign flips if 'b' and 'd' have opposite signs.

Additional Information: Properties of Correlation

The correlation coefficient is a powerful statistical measure with several important properties:

  • Range: The value of the correlation coefficient \(r\) is always between -1 and +1, inclusive (\(-1 \le r \le +1\)).
  • Direction: A positive correlation (\(r > 0\)) indicates that as one variable increases, the other variable tends to increase. A negative correlation (\(r < 0\)) indicates that as one variable increases, the other variable tends to decrease.
  • Strength: The closer the absolute value of \(r\) is to 1, the stronger the linear relationship. A value of 0 indicates no linear relationship.
  • Invariance to Scale and Location (with same sign): Adding a constant to a variable (location shift) or multiplying a variable by a positive constant (scale) does not change the correlation coefficient with another variable. That is, if \(U = a + bX\) with \(b > 0\), then \(r_{UY} = r_{XY}\). Similarly, if \(V = c + dY\) with \(d > 0\), then \(r_{XV} = r_{XY}\).
  • Sign Change with Negative Scaling: If a variable is multiplied by a negative constant, the sign of the correlation coefficient with another variable is reversed. If \(U = a + bX\) with \(b < 0\), then \(r_{UY} = -r_{XY}\).
  • Units: The correlation coefficient is a dimensionless quantity, meaning it does not have units. It is just a number.

Understanding these properties, especially the effect of linear transformations, is crucial when working with statistical data.

Was this answer helpful?

Important Questions from Forecasting

  1. Name the human resource demand (need) forecasting technique, which solicits estimates of personnel needs from a group of experts, usually managers. The HRP experts act as intermediaries, summarise the various responses and report the findings back to the experts. The experts are surveyed again after they receive this feedback. Summaries and surveys are repeated until the experts' opinions begin to agree. The agreement reached is the forecast of the personnel needs.

    Select the correct option :

  2. The sensitivity of forecast in simple moving average forecasting method, for the increase of the length of average period,

  3. For a product, the forecast and the actual sales for December 2008 were 25 and 20 respectively. If the exponential smoothing constant (α) is taken as 0.2, the forecast sales for January 2009 would be.

  4. For a product the forecast and actual sales for December 2002 were 25 and 20 respectively. If the exponential smoothing constant is taken as 0.2, then forecast sale for January 2003 would be

  5. The difference between the actual demand for any time period and the forecast for the same period is termed as _______.
Need Expert Advice?
Test Series
NDA img
Defence
NDA 2026 Mock Test Series (Latest Pattern)
503 Tests 1 Tests Free
1057 Attempts
4.6(136)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App