The correlation coefficient between two variables X and Y is found to be 0.6. All the observations on X and Y are transformed using the transformations U = 2 – 3X and V = 4Y + 1. The correlation coefficient between the transformed variables U and V will be
-0.6
The question asks how the correlation coefficient between two variables, X and Y, changes when both variables undergo specific linear transformations. We are given the initial correlation coefficient between X and Y, and the equations for the transformations.
The correlation coefficient, denoted by \(r_{XY}\), measures the strength and direction of the linear relationship between two variables X and Y. Its value ranges from -1 to +1.
We are given that the correlation coefficient between X and Y is \(r_{XY} = 0.6\).
The transformations are given as:
These are linear transformations. A linear transformation of a variable X is of the form \(U = a + bX\), where 'a' and 'b' are constants. In our case for variable X, \(a=2\) and \(b=-3\). For variable Y, the transformation is \(V = c + dY\), where \(c=1\) and \(d=4\).
Let's examine how these transformations affect the covariance and standard deviations, which are components of the correlation coefficient formula. The correlation coefficient between U and V is given by:
\(r_{UV} = \frac{Cov(U, V)}{\sigma_U \sigma_V}\)
Where \(Cov(U, V)\) is the covariance between U and V, \(\sigma_U\) is the standard deviation of U, and \(\sigma_V\) is the standard deviation of V.
For linear transformations \(U = a + bX\) and \(V = c + dY\):
The covariance between U and V is related to the covariance between X and Y by:
\(Cov(U, V) = Cov(a + bX, c + dY)\)
Using the properties of covariance, \(Cov(a_1 + b_1X_1, a_2 + b_2X_2) = b_1 b_2 Cov(X_1, X_2)\), we get:
\(Cov(U, V) = (b)(d) Cov(X, Y)\)
In our case, \(b = -3\) and \(d = 4\), so:
\(Cov(U, V) = (-3)(4) Cov(X, Y) = -12 Cov(X, Y)\)
The standard deviation of U is related to the standard deviation of X by:
\(\sigma_U = \sqrt{Var(U)} = \sqrt{Var(a + bX)}\)
Using the property \(Var(a + bX) = b^2 Var(X)\), we get:
\(\sigma_U = \sqrt{b^2 Var(X)} = |b| \sqrt{Var(X)} = |b| \sigma_X\)
In our case, \(b = -3\), so \(\sigma_U = |-3| \sigma_X = 3 \sigma_X\).
Similarly, the standard deviation of V is related to the standard deviation of Y by:
\(\sigma_V = \sqrt{Var(V)} = \sqrt{Var(c + dY)}\)
\(\sigma_V = \sqrt{d^2 Var(Y)} = |d| \sqrt{Var(Y)} = |d| \sigma_Y\)
In our case, \(d = 4\), so \(\sigma_V = |4| \sigma_Y = 4 \sigma_Y\).
Now substitute these into the formula for \(r_{UV}\):
\(r_{UV} = \frac{Cov(U, V)}{\sigma_U \sigma_V} = \frac{(b)(d) Cov(X, Y)}{|b| \sigma_X |d| \sigma_Y}\)
\(r_{UV} = \frac{(bd)}{|bd|} \frac{Cov(X, Y)}{\sigma_X \sigma_Y}\)
We know that \(r_{XY} = \frac{Cov(X, Y)}{\sigma_X \sigma_Y}\), so:
\(r_{UV} = \frac{(bd)}{|bd|} r_{XY}\)
The term \(\frac{(bd)}{|bd|}\) is equal to +1 if b and d have the same sign, and -1 if b and d have opposite signs. In this problem, \(b = -3\) (negative) and \(d = 4\) (positive). Since they have opposite signs, \(\frac{(bd)}{|bd|} = -1\).
Therefore, \(r_{UV} = -r_{XY}\).
Given \(r_{XY} = 0.6\), the correlation coefficient between U and V is:
\(r_{UV} = -(0.6) = -0.6\)
The correlation coefficient between the transformed variables U and V is -0.6.
This result shows that while scaling and shifting variables linearly does not change the magnitude of the correlation coefficient (it remains 0.6), it can change its sign if the scaling factors (the 'b' and 'd' values) have opposite signs.
| Original Variables | Transformed Variables | Transformation Type | Effect on Correlation Coefficient |
|---|---|---|---|
| X, Y | \(U = a + bX\) | Linear (shift and scale) | Correlation with other variables changes based on 'b'. |
| X, Y | \(V = c + dY\) | Linear (shift and scale) | Correlation with other variables changes based on 'd'. |
| X, Y (with \(r_{XY}\)) | \(U = a + bX\), \(V = c + dY\) | Linear (both variables) | \(r_{UV} = \frac{(bd)}{|bd|} r_{XY}\). The sign flips if 'b' and 'd' have opposite signs. |
The correlation coefficient is a powerful statistical measure with several important properties:
Understanding these properties, especially the effect of linear transformations, is crucial when working with statistical data.
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