All Exams Test series for 1 year @ ₹349 only
Question

The correlation coefficient between two variables X and Y is found to be 0.6. All the observations on X and Y are transformed using the transformations U = 2 – 3X and V = 4Y + 1. The correlation coefficient between the transformed variables U and V will be

The correct answer is

-0.6

Understanding Correlation Coefficient and Linear Transformations

The question asks how the correlation coefficient between two variables, X and Y, changes when both variables undergo specific linear transformations. We are given the initial correlation coefficient between X and Y, and the equations for the transformations.

The correlation coefficient, denoted by \(r_{XY}\), measures the strength and direction of the linear relationship between two variables X and Y. Its value ranges from -1 to +1.

We are given that the correlation coefficient between X and Y is \(r_{XY} = 0.6\).

The transformations are given as:

  • \(U = 2 - 3X\)
  • \(V = 4Y + 1\)

These are linear transformations. A linear transformation of a variable X is of the form \(U = a + bX\), where 'a' and 'b' are constants. In our case for variable X, \(a=2\) and \(b=-3\). For variable Y, the transformation is \(V = c + dY\), where \(c=1\) and \(d=4\).

Effect of Linear Transformations on Correlation Coefficient

Let's examine how these transformations affect the covariance and standard deviations, which are components of the correlation coefficient formula. The correlation coefficient between U and V is given by:

\(r_{UV} = \frac{Cov(U, V)}{\sigma_U \sigma_V}\)

Where \(Cov(U, V)\) is the covariance between U and V, \(\sigma_U\) is the standard deviation of U, and \(\sigma_V\) is the standard deviation of V.

For linear transformations \(U = a + bX\) and \(V = c + dY\):

The covariance between U and V is related to the covariance between X and Y by:

\(Cov(U, V) = Cov(a + bX, c + dY)\)

Using the properties of covariance, \(Cov(a_1 + b_1X_1, a_2 + b_2X_2) = b_1 b_2 Cov(X_1, X_2)\), we get:

\(Cov(U, V) = (b)(d) Cov(X, Y)\)

In our case, \(b = -3\) and \(d = 4\), so:

\(Cov(U, V) = (-3)(4) Cov(X, Y) = -12 Cov(X, Y)\)

The standard deviation of U is related to the standard deviation of X by:

\(\sigma_U = \sqrt{Var(U)} = \sqrt{Var(a + bX)}\)

Using the property \(Var(a + bX) = b^2 Var(X)\), we get:

\(\sigma_U = \sqrt{b^2 Var(X)} = |b| \sqrt{Var(X)} = |b| \sigma_X\)

In our case, \(b = -3\), so \(\sigma_U = |-3| \sigma_X = 3 \sigma_X\).

Similarly, the standard deviation of V is related to the standard deviation of Y by:

\(\sigma_V = \sqrt{Var(V)} = \sqrt{Var(c + dY)}\)

\(\sigma_V = \sqrt{d^2 Var(Y)} = |d| \sqrt{Var(Y)} = |d| \sigma_Y\)

In our case, \(d = 4\), so \(\sigma_V = |4| \sigma_Y = 4 \sigma_Y\).

Calculating the New Correlation Coefficient

Now substitute these into the formula for \(r_{UV}\):

\(r_{UV} = \frac{Cov(U, V)}{\sigma_U \sigma_V} = \frac{(b)(d) Cov(X, Y)}{|b| \sigma_X |d| \sigma_Y}\)

\(r_{UV} = \frac{(bd)}{|bd|} \frac{Cov(X, Y)}{\sigma_X \sigma_Y}\)

We know that \(r_{XY} = \frac{Cov(X, Y)}{\sigma_X \sigma_Y}\), so:

\(r_{UV} = \frac{(bd)}{|bd|} r_{XY}\)

The term \(\frac{(bd)}{|bd|}\) is equal to +1 if b and d have the same sign, and -1 if b and d have opposite signs. In this problem, \(b = -3\) (negative) and \(d = 4\) (positive). Since they have opposite signs, \(\frac{(bd)}{|bd|} = -1\).

Therefore, \(r_{UV} = -r_{XY}\).

Given \(r_{XY} = 0.6\), the correlation coefficient between U and V is:

\(r_{UV} = -(0.6) = -0.6\)

The correlation coefficient between the transformed variables U and V is -0.6.

This result shows that while scaling and shifting variables linearly does not change the magnitude of the correlation coefficient (it remains 0.6), it can change its sign if the scaling factors (the 'b' and 'd' values) have opposite signs.

Revision Table: Correlation Transformation Summary

Original Variables Transformed Variables Transformation Type Effect on Correlation Coefficient
X, Y \(U = a + bX\) Linear (shift and scale) Correlation with other variables changes based on 'b'.
X, Y \(V = c + dY\) Linear (shift and scale) Correlation with other variables changes based on 'd'.
X, Y (with \(r_{XY}\)) \(U = a + bX\), \(V = c + dY\) Linear (both variables) \(r_{UV} = \frac{(bd)}{|bd|} r_{XY}\). The sign flips if 'b' and 'd' have opposite signs.

Additional Information: Properties of Correlation

The correlation coefficient is a powerful statistical measure with several important properties:

  • Range: The value of the correlation coefficient \(r\) is always between -1 and +1, inclusive (\(-1 \le r \le +1\)).
  • Direction: A positive correlation (\(r > 0\)) indicates that as one variable increases, the other variable tends to increase. A negative correlation (\(r < 0\)) indicates that as one variable increases, the other variable tends to decrease.
  • Strength: The closer the absolute value of \(r\) is to 1, the stronger the linear relationship. A value of 0 indicates no linear relationship.
  • Invariance to Scale and Location (with same sign): Adding a constant to a variable (location shift) or multiplying a variable by a positive constant (scale) does not change the correlation coefficient with another variable. That is, if \(U = a + bX\) with \(b > 0\), then \(r_{UY} = r_{XY}\). Similarly, if \(V = c + dY\) with \(d > 0\), then \(r_{XV} = r_{XY}\).
  • Sign Change with Negative Scaling: If a variable is multiplied by a negative constant, the sign of the correlation coefficient with another variable is reversed. If \(U = a + bX\) with \(b < 0\), then \(r_{UY} = -r_{XY}\).
  • Units: The correlation coefficient is a dimensionless quantity, meaning it does not have units. It is just a number.

Understanding these properties, especially the effect of linear transformations, is crucial when working with statistical data.

Was this answer helpful?

Important Questions from Forecasting

  1. Which of the following lines is known as the trend line?

  2. An XYZ television supplier found a demand of 200 sets in July, 225 sets in August and 245 sets in September. Find the demand forecast for the month for the month of October using simple average method.

  3. Name the human resource demand (need) forecasting technique, which solicits estimates of personnel needs from a group of experts, usually managers. The HRP experts act as intermediaries, summarise the various responses and report the findings back to the experts. The experts are surveyed again after they receive this feedback. Summaries and surveys are repeated until the experts' opinions begin to agree. The agreement reached is the forecast of the personnel needs.

    Select the correct option :

  4. Which of the following is a technique used for forecasting?

  5. In a time series forecasting model, the demands for five time periods were 10, 13, 15, 18 and 22. A linear regression fit resulted in an equation F = 6.9 + 2.9t where F is the forecast for period t. The sum of the absolute deviations for the five data is

Need Expert Advice?

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App