The given transformation involves converting a hydroxy ketone to a methoxy ketone through several steps. Let's break down the processes involved in this transformation:

1. Deprotonation: The process begins with the deprotonation of the alcohol group, which involves removing a proton (H⁺) from the OH group using a base such as NaH. This forms an alkoxide ion, which is a good nucleophile.
2. Retro-aldol Reaction: The alkoxide ion can lead to a retro-aldol reaction where the C-C bond adjacent to the alkoxide group breaks, forming an enolate and releasing an aldehyde or ketone fragment.
3. Aldol Reaction: The enolate ion acts as a nucleophile and can attack the carbonyl group of the aldehyde or ketone fragment, reforming the C-C bond in a new configuration. This results in a new β-hydroxy ketone.
4. O-methylation: Finally, the oxygen of the alcohol group is methylated using methyl iodide (MeI), which replaces the hydrogen of the OH group with a methyl group (CH₃), resulting in a methoxy ketone.

Based on the steps outlined, the correct sequence of processes involved in the transformation is:

• i. deprotonation
• ii. retro-aldol reaction
• iii. aldol reaction
• iv. O-methylation

Therefore, the correct answer is the process sequence: deprotonation, retro-aldol reaction, aldol reaction, and O-methylation.