\(K_2SO_4 \text{ (aq.)} + BaCl_2 \text{ (aq.)} \rightarrow 2KCl \text{ (aq.)} + BaSO_4\downarrow \text{ (solid)}\)
is an example of:
The provided chemical reaction is:
\(K_2SO_4 \text{ (aq.)} + BaCl_2 \text{ (aq.)} \rightarrow 2KCl \text{ (aq.)} + BaSO_4\downarrow \text{ (solid)}\)
Let's analyze this reaction to understand why it is classified as a double displacement reaction.
In this reaction, we start with two ionic compounds dissolved in water:
When these two aqueous solutions are mixed, the ions present are \(K^+\), \(SO_4^{2-}\), \(Ba^{2+}\), and \(Cl^-\). In a double displacement reaction, the positive ions (cations) and negative ions (anions) of the two reactant compounds switch partners.
This results in the formation of two new compounds:
The overall process involves the exchange of ions: the \(K^+\) ions were initially with \(SO_4^{2-}\) and the \(Ba^{2+}\) ions were with \(Cl^-\). After the reaction, \(K^+\) ions are with \(Cl^-\) and \(Ba^{2+}\) ions are with \(SO_4^{2-}\). This characteristic exchange defines it as a double displacement reaction.
Let's see why the other options are not suitable:
The reaction \(K_2SO_4 \text{ (aq.)} + BaCl_2 \text{ (aq.)} \rightarrow 2KCl \text{ (aq.)} + BaSO_4\downarrow \text{ (solid)}\) is a clear example of a double displacement reaction because the cations (\(K^+\) and \(Ba^{2+}\)) and anions (\(SO_4^{2-}\) and \(Cl^-\)) exchange partners between the two reacting ionic compounds.
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