The problem asks for the price of the cheapest furniture item given the average price of three items and the ratio of their prices.
Represent Prices using Ratio: Let the prices of the three furniture items be $3x$, $5x$, and $7x$, according to the given ratio $3 : 5 : 7$.
Use the Average Price Formula: The average price is calculated as the sum of prices divided by the number of items. $ \text{Average Price} = \frac{\text{Sum of Prices}}{\text{Number of Items}} $ Given the average price is ₹5,310 and there are 3 items, we have:
$ ₹5,310 = \frac{3x + 5x + 7x}{3} $Solve for the Variable ($x$): Combine the terms in the numerator: $ ₹5,310 = \frac{15x}{3} $ Simplify the fraction: $ ₹5,310 = 5x $ Now, isolate $x$ by dividing both sides by 5: $ x = \frac{₹5,310}{5} $ $ x = ₹1,062 $
Calculate the Cheapest Item's Price: The cheapest item corresponds to the smallest ratio part, which is 3. Therefore, its price is $3x$. $ \text{Price of Cheapest Item} = 3 \times x $ $ \text{Price of Cheapest Item} = 3 \times ₹1,062 $ $ \text{Price of Cheapest Item} = ₹3,186 $
The price of the cheapest item is ₹3,186.
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