The average of 20 numbers is 40. If the sum of the first 10 numbers is 380, what is the average of the remaining 10 numbers?
42
Sum of all 20 numbers = \(20 \times 40 = 800\).
Sum of the remaining 10 numbers = \(800 - 380 = 420\).
Average of the remaining 10 numbers = \(\frac{420}{10} = 42\).
Hence, the average of the remaining 10 numbers is 42.
Similar Questions
The sum of the first 10 numbers is 380, and the average of 20 numbers is 40. What is the average of the remaining 10 numbers?
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