Let the side length of the square be $s$. The area of the square is given as $d$. Therefore, we have:
The diagonal of a square ($D_{sq}$) is related to its side length $s$ by the formula $D_{sq} = s\sqrt{2}$. Since $s = \sqrt{d}$, the diagonal is:
The problem states that the diagonal of the square serves as the diameter of the circle ($D_{circle}$).
The radius ($r$) of the circle is half its diameter:
The area of a circle ($A_{circle}$) is calculated using the formula $A_{circle} = \pi r^2$. Substitute the value of $r$ we found:
Thus, the area of the circle is $\frac{1}{2}\pi d$.
In the given figure, $P, Q$, and $R$ are three points on a circle of radius 10 cm with $O$ as its center, $\overline{PQ} = \overline{RQ}$, and $\angle PQR = 45^\circ$. The figure is representative.
The area of the shaded region $PQRO$ is ______________ cm$^2$.
