Let the side length of the square be $s$. The area of the square is given as $d$. Therefore, we have:
The diagonal of a square ($D_{sq}$) is related to its side length $s$ by the formula $D_{sq} = s\sqrt{2}$. Since $s = \sqrt{d}$, the diagonal is:
The problem states that the diagonal of the square serves as the diameter of the circle ($D_{circle}$).
The radius ($r$) of the circle is half its diameter:
The area of a circle ($A_{circle}$) is calculated using the formula $A_{circle} = \pi r^2$. Substitute the value of $r$ we found:
Thus, the area of the circle is $\frac{1}{2}\pi d$.
In the given figure, PQRS is a square of side 2 cm and PLMN is a rectangle. The corner L of the rectangle is on the side QR. Side MN of the rectangle passes through the corner S of the square.
What is the area (in cm²) of the rectangle PLMN?
Note: The figure shown is representative.

A regular dodecagon (12-sided regular polygon) is inscribed in a circle of radius $r$ cm as shown in the figure. The side of the dodecagon is $d$ cm. All the triangles (numbered 1 to 12) in the figure are used to form squares of side $r$ cm and each numbered triangle is used only once to form a square.
The number of squares that can be formed and the number of triangles required to form each square, respectively, are:
Note: The figure shown is representative.