The addition of a pole to the forward path transfer function of a closed loop system, generally has the effect of
Increasing the maximum overshoot
What a pole does to the loop. Adding a pole to G(s) inserts an extra lag: each pole contributes up to −90° of phase and an extra −20 dB/decade of roll-off. Both effects work against stability.
The frequency-domain reading. The extra phase lag pulls the open-loop phase curve down, so the phase crosses −180° at a lower frequency and the phase margin shrinks. Since phase margin and damping are tied together by the familiar rule of thumb
\(PM \approx 100\,\xi\ \text{degrees}\)
a smaller phase margin means a smaller damping ratio ξ. And overshoot rises steeply as damping falls:
\(M_p=e^{-\pi\xi/\sqrt{1-\xi^{2}}}\times100\%\)
so the maximum overshoot increases.
The root-locus reading, which shows the same thing. Adding a pole pushes the asymptotes of the root locus to the right: the centroid moves right and the asymptote angles widen, so the complex branches bend towards — and eventually into — the right half plane. The closed-loop poles therefore sit closer to the jω axis at any given gain, i.e. less damped, more oscillatory, larger overshoot, and the system becomes unstable at a lower gain.
The mirror-image result is worth learning alongside it: adding a zero to the forward path contributes phase lead, pulls the locus to the left, raises the phase margin and reduces the overshoot. That is precisely why a derivative or lead compensator (a zero) is used to tame an oscillatory system, while integral action (a pole at the origin) improves steady-state accuracy at the cost of transient behaviour.
| Added element | Phase | Root locus | Overshoot | Stability |
|---|---|---|---|---|
| Pole | lag | shifts right | increases | reduced |
| Zero | lead | shifts left | decreases | improved |
Hence, adding a pole generally has the effect of increasing the maximum overshoot.
The step, ramp and parabolic test input signals can respectively be expressed as
Assertion (A) : In control systems, steady state response in the final requirement for calculating the efficiency of the system.
Reason (R) : The transient response is also critical for the determination of the steady state response.
If the characteristic equation of a closed loop system is S2 + 2S + 2 = 0, then the system is
The open loop transfer function of a unity feedback control system is given by \(G(s)=\frac{25}{s(s+5)}\). The natural frequency of oscillator is fixed.
Arrange the damped frequency of oscillation for the following damping ratio in ascending order
A. \(\xi = 0.5\)
B. \(\xi = 0.1\)
C. \(\xi = 0.3\)
D. \(\xi = 0.25\)
E. \(\xi = 0.4\)
Choose the correct answer from the options given below :
Match the following lists :
| List - I | List - II |
| a. Negative real and simple roots | i. Sustained oscillatory |
| b. Negative real and equal roots | ii. Overdamped |
| c. Complex conjugate roots | iii. Critically damped |
| d. Imaginary conjugate roots | iv. Underdamped |
Correct codes are :
consider a unity feedback control system for an open loop transfer function \(G(s)=\frac{5}{s(s+1)}\). Arrange the time constant in ascending order at different value of damping ratio of
A. \(\xi=3\)
B. \(\xi=7\)
C. \(\xi=1\)
D. \(\xi=10\)
E. \(\xi=5\)
Choose the correct answer from the options given below :
Match the LIST-I with LIST-II
| LIST-I Transfer function | LIST-II Step response |
| A. $\frac{25}{S^2+25}$ | I. ![]() |
| B. $\frac{36}{S^2+70S+36}$ | II. ![]() |
| C. $\frac{36}{S^2+12S+36}$ | III. ![]() |
| D. $\frac{36}{S^2+7S+49}$ | IV. ![]() |
Choose the correct answer from the options given below:
The step, ramp and parabolic test input signals can respectively be expressed as
Assertion (A) : In control systems, steady state response in the final requirement for calculating the efficiency of the system.
Reason (R) : The transient response is also critical for the determination of the steady state response.
If the characteristic equation of a closed loop system is S2 + 2S + 2 = 0, then the system is
The open loop transfer function of a unity feedback control system is given by \(G(s)=\frac{25}{s(s+5)}\). The natural frequency of oscillator is fixed.
Arrange the damped frequency of oscillation for the following damping ratio in ascending order
A. \(\xi = 0.5\)
B. \(\xi = 0.1\)
C. \(\xi = 0.3\)
D. \(\xi = 0.25\)
E. \(\xi = 0.4\)
Choose the correct answer from the options given below :