Suppose X = {1, 2, 3, 4} and R is a relation on X. If R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1), (2, 3), (3, 2), (1, 3), (3, 1)}, then which one of the following is correct?
R is symmetric and transitive, but not reflexive
Let's analyze the given relation R on the set X to determine its properties: reflexive, symmetric, and transitive. The set is X = {1, 2, 3, 4}, and the relation R is given by R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1), (2, 3), (3, 2), (1, 3), (3, 1)}.
A relation R on a set X is said to be reflexive if for every element $x \in X$, the pair $(x, x)$ belongs to R. In simpler terms, every element must be related to itself.
For the given set X = {1, 2, 3, 4}, for R to be reflexive, the following pairs must be present in R:
Let's look at the given relation R:
R = {(1, 1), (2, 2), (3, 3), (1, 2), (2, 1), (2, 3), (3, 2), (1, 3), (3, 1)}
We can see that (1, 1), (2, 2), and (3, 3) are present in R. However, the pair (4, 4) is missing from R. Since there is an element in X (which is 4) that is not related to itself, the relation R is not reflexive.
Conclusion for Reflexivity: R is not reflexive.
A relation R on a set X is said to be symmetric if for every pair $(x, y)$ in R, the reversed pair $(y, x)$ also belongs to R. This means that if x is related to y, then y must also be related to x.
Let's examine each pair $(x, y)$ in R and check if $(y, x)$ is also in R:
For every pair $(x, y)$ in R, the corresponding pair $(y, x)$ is also found in R.
Conclusion for Symmetry: R is symmetric.
A relation R on a set X is said to be transitive if for every pair $(x, y)$ in R and every pair $(y, z)$ in R, the pair $(x, z)$ also belongs to R. This means if x is related to y, and y is related to z, then x must also be related to z.
We need to check all possible combinations of pairs $(x, y) \in R$ and $(y, z) \in R$. If such pairs exist, we must verify that $(x, z) \in R$.
Let's list some examples:
The elements involved in the pairs in R are only {1, 2, 3}. The element 4 is not involved in any pairs in R. If (x, y) $\in$ R and (y, z) $\in$ R, then x, y, and z must be from the set {1, 2, 3}. The given relation R restricted to the set {1, 2, 3} contains all possible pairs between elements from {1, 2, 3}, i.e., it is the universal relation on {1, 2, 3}. The universal relation on any set is always transitive. Thus, if (x, y) $\in$ R and (y, z) $\in$ R, then x, y, z $\in$ {1, 2, 3}, and (x, z) must be in R because all pairs of elements from {1, 2, 3} are in R.
After checking all combinations (which can be extensive but follows the pattern seen above), we find that the transitive property holds for R.
Conclusion for Transitivity: R is transitive.
Based on our analysis:
Therefore, the relation R is symmetric and transitive, but not reflexive.
The relation R on set X = {1, 2, 3, 4} is found to be symmetric and transitive, but not reflexive. This matches one of the given options describing the properties of the relation R.
| Property | Definition | Check for Relation R | Conclusion |
|---|---|---|---|
| Reflexive | For all $x \in X$, $(x, x) \in R$ | (4, 4) $\notin$ R (since 4 $\in$ X) | Not Reflexive |
| Symmetric | For all $(x, y) \in R$, $(y, x) \in R$ | Checked all pairs; holds true for R | Symmetric |
| Transitive | For all $(x, y) \in R$ and $(y, z) \in R$, $(x, z) \in R$ | Checked combinations; holds true for R | Transitive |
| Property | Condition |
|---|---|
| Reflexive | $(a, a) \in R$ for all $a \in$ set A |
| Symmetric | If $(a, b) \in R$, then $(b, a) \in R$ for all $a, b \in$ set A |
| Transitive | If $(a, b) \in R$ and $(b, c) \in R$, then $(a, c) \in R$ for all $a, b, c \in$ set A |
Relations are fundamental concepts in mathematics and computer science, used to describe relationships between elements of sets. Understanding the properties like reflexive, symmetric, and transitive helps classify different types of relations.
When testing these properties, it is crucial to consider all elements in the set X, not just those that appear in the ordered pairs listed in the relation R.
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2. The relation g defined by \(g(x)= \begin{cases}x^2, & 0 \leq x \leq 4 \\ 3 x, & 4 \leq x \leq 8\end{cases}\) is a function.
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