Six times the present age of P exceeds the present age of Q by 46 years. After 10 years, six times Q's age will be 18 years less than five times P's age at that time. What is the present age of Q (in years)?
This solution demonstrates how to determine the present age of Q using the information provided in the word problem involving P and Q. We will employ algebraic methods to solve the system of equations.
To begin, let's assign variables to represent the unknown ages:
The problem provides two key pieces of information that can be converted into mathematical equations.
Statement: "Six times the present age of P exceeds the present age of Q by 46 years."
Translating this into an equation:
$6P = Q + 46 \quad (1)$
Statement: "After 10 years, six times Q's age will be 18 years less than five times P's age at that time."
Ages after 10 years:
Translating the statement into an equation:
$6(Q + 10) = 5(P + 10) - 18$
Simplifying this equation:
$6Q + 60 = 5P + 50 - 18$
$6Q + 60 = 5P + 32$
Rearranging terms to isolate \(6Q\):
$6Q = 5P + 32 - 60$
$6Q = 5P - 28 \quad (2)$
We now have a system of two linear equations:
We need to solve this system to find the value of \(Q\).
From Equation (1), rearrange to solve for \(Q\):
\(Q = 6P - 46\)
Substitute the expression for \(Q\) into Equation (2):
$6(6P - 46) = 5P - 28$
Expand and solve the equation for \(P\):
$36P - 276 = 5P - 28$
Combine \(P\) terms:
$36P - 5P = 276 - 28$
$31P = 248$
Solve for \(P\):
$P = \frac{248}{31}$
$P = 8$
The present age of P is 8 years.
Using the relationship from Step 1 (\(Q = 6P - 46\)) and the value \(P = 8\):
\(Q = 6(8) - 46\)
\(Q = 48 - 46\)
\(Q = 2\)
Therefore, the present age of Q is 2 years.
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