Eight years ago, the ratio of ages of A and B was 5 ∶ 4. The ratio of their present ages is 6 ∶ 5. What will be the sum (in years) of the ages of A and B after 7 years from now?
102
This problem involves finding the sum of the ages of two individuals, A and B, after a certain number of years, based on their age ratios at different points in time. We are given the ratio of their ages eight years ago and the ratio of their present ages.
We are given two key pieces of information about the ages of A and B:
We need to use these ratios to find their current ages and then calculate the sum of their ages seven years from now.
Let's break down the problem into manageable steps.
Let the ages of A and B eight years ago be $5x$ and $4x$ years respectively, based on the given ratio 5:4.
If their ages eight years ago were $5x$ and $4x$, then their present ages must be:
We are given that the ratio of their present ages is 6 : 5. So, we can write the equation:
\begin{equation*} \frac{\text{Present age of A}}{\text{Present age of B}} = \frac{6}{5} \end{equation*}
Substituting the expressions for their present ages:
\begin{equation*} \frac{5x + 8}{4x + 8} = \frac{6}{5} \end{equation*}
Now, we solve this equation for the variable $x$ by cross-multiplication:
\begin{align*} 5 \times (5x + 8) &= 6 \times (4x + 8) \\ 25x + 40 &= 24x + 48 \end{align*}
Subtract $24x$ from both sides:
\begin{align*} 25x - 24x + 40 &= 48 \\ x + 40 &= 48 \end{align*}
Subtract 40 from both sides:
\begin{equation*} x = 48 - 40 \\ x = 8 \end{equation*}
Now that we have the value of $x$, we can find their present ages:
Let's quickly check the present age ratio: $48 : 40$. Dividing both by 8, we get $6 : 5$, which matches the given information.
We need to find the sum of their ages after 7 years from now. First, let's find their ages after 7 years:
Finally, we find the sum of their ages after 7 years:
Sum of ages after 7 years = Age of A after 7 years + Age of B after 7 years
Sum $= 55 + 47 = 102$ years.
Therefore, the sum of the ages of A and B after 7 years from now will be 102 years.
| Time Period | A's Age | B's Age | Ratio |
|---|---|---|---|
| 8 years ago | $5x$ | $4x$ | 5 : 4 |
| Present | $5x + 8$ | $4x + 8$ | 6 : 5 |
| After 7 years | $(5x + 8) + 7$ | $(4x + 8) + 7$ | |
| Calculated Present (x=8) | 48 | 40 | 48:40 = 6:5 |
| Calculated After 7 years | 48 + 7 = 55 | 40 + 7 = 47 |
| Information Type | Details |
|---|---|
| Age ratio 8 years ago | 5 : 4 |
| Present age ratio | 6 : 5 |
| Calculated Present Age of A | 48 years |
| Calculated Present Age of B | 40 years |
| Age of A after 7 years | 55 years |
| Age of B after 7 years | 47 years |
| Sum of ages after 7 years | 102 years |
Age-related problems in mathematics often involve ratios and setting up linear equations. Here are some tips:
These types of problems are common in competitive exams and help test your ability to translate word problems into algebraic models and solve them systematically.
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