Question
Six teams DD, MI, RCB, KKR, RR and CSK are compared on the basis of the number of matches won by them in 2019. DD won more matches than RR and RCB but less matches than MI and CSK. KKR won more matches than MI but less matches than CSK.
Who won the most numbers of matches?
This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
CSK
Analyzing Match Wins for 2019 Cricket Teams
The question asks to identify the team with the most wins in 2019 based on several comparative statements.
Deriving Team Rankings
Let's represent the number of matches won by each team using inequalities:
- DD won more than RR and RCB: $DD > RR$ and $DD > RCB$.
- DD won less than MI and CSK: $MI > DD$ and $CSK > DD$.
- KKR won more than MI: $KKR > MI$.
- KKR won less than CSK: $CSK > KKR$.
Combining Comparisons
We can combine these inequalities to establish a ranking:
- From $CSK > KKR$ and $KKR > MI$, we get the sequence: $CSK > KKR > MI$.
- We know $MI > DD$. Combining this with the previous step gives: $CSK > KKR > MI > DD$.
- We also know $DD > RR$ and $DD > RCB$.
- Therefore, the complete order from most wins to least is: $CSK > KKR > MI > DD > (RR, RCB)$. The order between RR and RCB is not specified, but they are both below DD.
Identifying the Top Team
Based on the derived order $CSK > KKR > MI > DD > (RR, RCB)$, the team that won the most matches is CSK.
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