Six persons that is A, B, C, X, Y and Z who all are sitting around a circular table facing outside. They all are of different age. Y is third youngest person. Only two persons sit between X and Y. Z sits second to the left of C, who is 20 Years of age. The one who is second oldest person is of 24 Years of age. Z is elder than A and C but not the eldest. C sits on the immediate right of X. B is elder than A and Z. A and Z are not immediate neighbours. The one who is the youngest is less than 20 years of age. A is not younger than Y. What will be the possible age of A?
22 Years
Step 1 — Seating. Everyone faces outside, so (seen from above) a person's right is clockwise and left is anticlockwise. C is immediately right of X, so C is the next seat clockwise from X. Z is second to the left of C, i.e. two seats anticlockwise from C, which is the seat immediately left of X. Only two persons sit between X and Y, so Y is directly opposite X.
Step 2 — The two seats left are one between C and Y and one between Y and Z. A and Z are not neighbours, so A sits between C and Y and B sits between Y and Z.
Step 3 — Ages. B is older than A and Z; Z is older than A and C but is not the eldest; A is older than Y (A is not younger than Y and all ages differ). So B > Z > A > Y. Y is the third youngest, so exactly two persons are younger than Y, and they must be C and X. The order from the eldest is B, Z, A, Y, then C and X.
Step 4 — Z is the second oldest, so Z is 24 years. C is 20 years and the youngest is below 20, so X is the youngest. Y is older than C and A is older than Y but younger than Z, so \(20 \lt Y \lt A \lt 24\).
Hence A can be 22 years (with Y at 21 years). 25 years and 27 years would make A older than the 24-year-old second oldest person, and 20 years is C's age, which is below Y.
22 Years option is correct.
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