Simplify the following expression. (4x + 1)2 − (4x + 3) (4x − 1)
4
The problem asks us to simplify the algebraic expression \( (4x + 1)^2 - (4x + 3)(4x - 1) \). To do this, we need to expand the terms and then combine like terms. This involves using algebraic identities and careful calculation.
Let's break down the simplification into steps:
We use the algebraic identity \( (a+b)^2 = a^2 + 2ab + b^2 \). Here, \(a = 4x\) and \(b = 1\).
\( (4x + 1)^2 = (4x)^2 + 2(4x)(1) + 1^2 \)
\( = 16x^2 + 8x + 1 \)
We can use the distributive property (often called FOIL) or recognize a pattern similar to \( (a+b)(a-c) \) or simply expand it step by step:
Adding these together:
\( (4x + 3)(4x - 1) = 16x^2 - 4x + 12x - 3 \)
\( = 16x^2 + 8x - 3 \)
Now we substitute the expanded forms back into the original expression:
\( (16x^2 + 8x + 1) - (16x^2 + 8x - 3) \)
Remember to distribute the negative sign to every term inside the second parenthesis:
\( = 16x^2 + 8x + 1 - 16x^2 - 8x + 3 \)
Group the terms with \(x^2\), terms with \(x\), and constant terms:
\( = (16x^2 - 16x^2) + (8x - 8x) + (1 + 3) \)
\( = 0x^2 + 0x + 4 \)
\( = 4 \)
The simplified expression is \( 4 \).
Let's quickly check our steps and calculations. The expansion of \( (4x+1)^2 \) is correct. The expansion of \( (4x+3)(4x-1) \) using FOIL is also correct. The subtraction and combining of like terms resulted in the cancellation of the \(x^2\) and \(x\) terms, leaving only the constant term.
The result of the simplification is indeed 4.
| Identity | Formula |
|---|---|
| Square of a Sum | \( (a+b)^2 = a^2 + 2ab + b^2 \) |
| Square of a Difference | \( (a-b)^2 = a^2 - 2ab + b^2 \) |
| Difference of Squares | \( a^2 - b^2 = (a+b)(a-b) \) |
| Product of Sum and Difference | \( (a+b)(a-c) = a^2 - ac + ba - bc \) (General FOIL) |
Simplifying algebraic expressions is a fundamental skill in algebra. It involves rewriting an expression in a simpler or more manageable form. This often requires applying properties of numbers, exponent rules, and algebraic identities.
In this specific problem, we used expansion and combining like terms to arrive at the simplified form. The expression simplified to a constant value, meaning its value does not depend on the variable \(x\).
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