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Simplify: \(\frac{2\sin^2A-\sin^4A+\cos^4A}{3\sin^4A-2\sin^6A+3\cos^4A-2\cos^6A}\)

This question was previously asked in
RRB Technician 2026 Grade 3 Question Paper (7-Oct-2026) (Shift 3)
The correct answer is

1

Numerator: \( \cos^4A-\sin^4A=(\cos^2A-\sin^2A)(\cos^2A+\sin^2A)=\cos^2A-\sin^2A \).

So numerator = \( 2\sin^2A+\cos^2A-\sin^2A=\sin^2A+\cos^2A=1 \).

Use \( \sin^4A+\cos^4A=1-2\sin^2A\cos^2A \) and \( \sin^6A+\cos^6A=1-3\sin^2A\cos^2A \).

Denominator = \( 3(1-2\sin^2A\cos^2A)-2(1-3\sin^2A\cos^2A)=3-6\sin^2A\cos^2A-2+6\sin^2A\cos^2A=1 \).

Expression = \( \frac{1}{1}=1 \).

Hence, the simplified value is 1.

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