If the roots of the equation \(x^2 + mx + n = 0\) are increased by the same quantity \(k\), then they become the roots of the equation \(x^2 + nx + m = 0\). What is the value of \((m+n)\)?
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Let the roots of \(x^2+mx+n=0\) be \(p\) and \(q\), so \(p+q=-m\) and \(pq=n\).
The new roots \(p+k\) and \(q+k\) satisfy \(x^2+nx+m=0\), so \((p+k)+(q+k)=-n\) and \((p+k)(q+k)=m\).
From the sum: \(-m+2k=-n \Rightarrow 2k=m-n\).
From the product: \(n-km+k^2=m\). Substituting \(k=\frac{m-n}{2}\) and simplifying gives \((n-m)(n+m+4)=0\).
Since \(k\) is a genuine (non-zero) shift, \(n \neq m\), so \(m+n=-4\).
Suppose \(p\) and \(q\) are positive integers where \(q\) is not a perfect square. If \(\dfrac{1}{p+\sqrt{q}}\) is a root of a quadratic equation having integer coefficients, then which of the following statements is/are correct?
I. The sum of the roots is \(2p\) times the product of the roots.
II. The sum of the reciprocals of the roots is equal to \(2p\).
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