Select the option that is related to the fifth letter-number cluster in the same way as the second letter-number cluster is related to the first letter-number cluster and fourth letter-number cluster is related to third letter-number cluster. (NOTE: Operations should be performed on the whole numbers, without breaking down the number into its constituent digits. E.g.13 - Operations on 13 such as adding /subtracting /multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed) SB760 : PY530 :: AR1040 : XO810 :: FK840 : ?
CH610
The chain gives two model relations, SB760 : PY530 and AR1040 : XO810, and the same relation must be applied to the fifth cluster FK840 to find the missing sixth cluster.
Split each cluster into its letter part and its number part and find the rule on each part separately.
Letters: each letter shifts back by 3. Check SB→PY: S−3=P and B−3=Y. Confirm on AR→XO: A−3=X and R−3=O. The −3 shift holds on both model pairs.
Numbers: the number decreases by 230 each time — \(760-230=530\) and \(1040-230=810\), confirming the constant subtraction.
Now apply both rules to FK840. Letters: F−3=C and K−3=H, giving the letter part CH.
Number: \(840-230=610\), giving the number part 610, so the cluster is CH610.
The concept is applying a fixed letter back-shift together with a fixed number subtraction. Hence the required cluster is CH610.
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