Select the letter that will replace the question mark (?) in the following series. L, S, M, P, N, M, O, J, P, ?
G
The given series is L, S, M, P, N, M, O, J, P, ?. We need to find the letter that replaces the question mark based on the pattern in the series.
Let's look at the alphabetical positions of the letters:
The series of alphabetical positions is: 12, 19, 13, 16, 14, 13, 15, 10, 16, ?
Looking closely at the sequence of letters, it appears there might be two different patterns interleaved within the main series.
Let's separate the letters at odd positions (1st, 3rd, 5th, 7th, 9th, ...):
L, M, N, O, P
Let's look at their positions:
12, 13, 14, 15, 16
This is a simple arithmetic progression where each term is increasing by 1. The pattern is $\text{Letter} + 1$.
Now, let's look at the letters at even positions (2nd, 4th, 6th, 8th, 10th, ...):
S, P, M, J, ?
Let's look at their positions:
19, 16, 13, 10, ?
This is also an arithmetic progression, but in decreasing order. Each term is decreasing by 3. The pattern is $\text{Letter} - 3$.
The question mark is at the 10th position, which is an even position. Therefore, the pattern from the second series (even positions) applies here.
The last known letter in the second series is J, which is at the 8th position in the original series and has an alphabetical position of 10.
Applying the pattern $\text{Letter} - 3$:
The position of the next letter = Position of J - 3
Position of the next letter = $10 - 3 = 7$
The 7th letter in the alphabet is G.
So, the letter that replaces the question mark is G.
| Position in Series | Letter | Alphabetical Position | Sub-series | Pattern |
|---|---|---|---|---|
| 1st | L | 12 | 1st sub-series (Odd) | +1 |
| 3rd | M | 13 | 1st sub-series (Odd) | |
| 5th | N | 14 | 1st sub-series (Odd) | |
| 7th | O | 15 | 1st sub-series (Odd) | |
| 9th | P | 16 | 1st sub-series (Odd) | |
| 2nd | S | 19 | 2nd sub-series (Even) | -3 |
| 4th | P | 16 | 2nd sub-series (Even) | |
| 6th | M | 13 | 2nd sub-series (Even) | |
| 8th | J | 10 | 2nd sub-series (Even) | |
| 10th | ? | 7 | 2nd sub-series (Even) |
By identifying the two interleaved series, we found that the second series follows a pattern of subtracting 3 from the alphabetical position of the previous letter in that sub-series. Applying this pattern to J (position 10) gives us a position of 7, which corresponds to the letter G.
| Concept | Description | Example Pattern |
|---|---|---|
| Alphabetical Position | Using the A=1, B=2, ... Z=26 value for letters. | A=1, E=5, I=9 (adds 4) |
| Arithmetic Progression | Adding or subtracting a constant value to the previous term's position. | B, D, F, H (positions 2, 4, 6, 8 - adds 2) |
| Interleaved Series | Two or more different patterns alternating within a single series. One pattern applies to terms at odd positions, another to terms at even positions (or other alternating groups). | A, Z, B, Y, C, X (A, B, C... and Z, Y, X...) |
| Skipping Letters | Patterns based on skipping a fixed number of letters in the alphabet. | A, C, E, G (skips 1 letter each time) |
Solving letter series questions requires careful observation and trying out different potential patterns. Here are some common strategies:
Practice with various types of series helps in quickly recognizing common patterns.
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