To find the total amount Ravi has to pay after one year with the given conditions, we need to use the formula for compound interest. Compound interest is calculated using the formula:
\(A = P \left(1 + \frac{r}{n}\right)^{nt}\)
where:
Substituting the given values into the formula, we get:
\(A = 16000 \left(1 + \frac{0.20}{4}\right)^{4 \times 1}\)
Simplifying further:
\(A = 16000 \left(1 + 0.05\right)^{4}\)
\(A = 16000 \left(1.05\right)^{4}\)
Calculating the power of 1.05 raised to 4:
\((1.05)^4 = 1.21550625\)
Now, substitute back to find A:
\(A = 16000 \times 1.21550625\)
Calculate the final amount:
\(A \approx 19448.10\)
Therefore, the amount that Ravi has to pay after one year is ₹19,448.10, which matches the first option.
Amar borrowed Rs. 10000 from Sachin at simple interest. After 4 years, Sachin received Rs. 5000 more than the amount given to Amar on loan. Find the rate of interest.
Simple interest accrued on the amount of Rs.14,000 is Rs. 1260 at the rate of 3 % per annum for t years. What would be the compound interest accrued on the same amount for the same years at 10 % per annum compounded annually?
Rishu deposited an amount of Rs. 950 at Compound Interest. The amount gets doubled of itself after 4 years. What will be the amount after 12 years?
Which of the following schemes of computing interest yields the maximum interest for a year?
On a certain sum, rate of interest per annum for the first two years is 4%. The rate of interest for next four years is 6% and for the next three years is 8%. If total simple interest earned at the end of 9 years is ₹ 1120, then the sum is: