Pipes A and pipe B can fill a tank at rate of 30 m 3/hr and 40 m 3/hr respectively. Together they fill the tank in 4 hours. Find the volume of the tank.
280 m 3
To find the volume of the tank, we can calculate the combined rate at which both pipes fill the tank together per hour.
Step 1: Find the combined rate of both pipes
Rate of Pipe A = \(30\text{ m}^3/\text{hr}\)
Rate of Pipe B = \(40\text{ m}^3/\text{hr}\)
\[\text{Combined Rate} = 30\text{ m}^3/\text{hr} + 40\text{ m}^3/\text{hr} = 70\text{ m}^3/\text{hr}\]
Step 2: Calculate the total volume of the tank
Since they take \(4\text{ hours}\) to completely fill the tank together, the volume is:
\[\text{Volume} = \text{Combined Rate} \times \text{Time}\]
\[\text{Volume} = 70\text{ m}^3/\text{hr} \times 4\text{ hours} = 280\text{ m}^3\]
Therefore, the volume of the tank is \(280\text{ m}^3\).
Correct Answer: Option 2 (\(280\text{ m}^3\))
Similar Questions
Thirty men can do a piece of work in 16 days working 8 hrs a day. How many men are needed to complete another work, which is twice the first one, in 10 days working 12 hrs a day?
The following are the steps involved in solving the above problem. Arrange them in sequential order.
A) M 2 = \(\rm\frac{30 \times 16 \times 8 \times 2x}{x \times 12 \times 10}\)
B) \(\rm\frac{30 \times 16 \times 8}{x}=\frac{M_2 \times 12 \times 10}{2 x}\)
C) \(\rm\frac{M_1 D_1 H_1}{ W_1}=\frac{M_2 D_2 H_2}{W_2}\)
D) M 2 = 64
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