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Question

Nikhil is 8 years younger than his brother Rohan. How old will Rohan be when he is twice as old as Nikhil?

This question was previously asked in
SSC CGL 2016 (Tier 1) Previous Year Question Paper (11-Sep-2016) (Shift 2)
The correct answer is

16 yr

Solving the Age Word Problem: Rohan and Nikhil

This question asks us to find Rohan's age in the future when a specific condition about his age relative to his younger brother, Nikhil, is met. We are given their current age difference and the future relationship between their ages.

Understanding the Problem

We know two main things:

  • Nikhil is 8 years younger than Rohan. This means Rohan is 8 years older than Nikhil. The age difference between them will always remain 8 years.
  • We want to find their ages at a future point in time when Rohan is exactly twice as old as Nikhil.

Setting up the Equations

Let's use variables to represent their ages at the future time we are interested in.

  • Let Rohan's age in the future be \(R_{future}\).
  • Let Nikhil's age in the future be \(N_{future}\).

From the problem statement, we can write two equations based on the conditions:

  1. The age difference is always 8 years. So, at the future time: \(R_{future} - N_{future} = 8\), which can be written as \(R_{future} = N_{future} + 8\).
  2. At this future time, Rohan will be twice as old as Nikhil: \(R_{future} = 2 \times N_{future}\).

Solving the Equations

Now we have a system of two simple linear equations:

\(R_{future} = N_{future} + 8\)
\(R_{future} = 2 N_{future}\)

We can solve this system by substituting the second equation into the first one. Since both equations are equal to \(R_{future}\), we can set them equal to each other:

\(N_{future} + 8 = 2 N_{future}\)

Now, we need to solve for \(N_{future}\):

Subtract \(N_{future}\) from both sides of the equation:

\(8 = 2 N_{future} - N_{future}\)
\(8 = N_{future}\)

So, Nikhil's age at that future point in time will be 8 years.

The question asks for Rohan's age at that future point. We can find Rohan's age (\(R_{future}\)) using either of the original equations. Let's use the second one, as it's simpler:

\(R_{future} = 2 \times N_{future}\)
\(R_{future} = 2 \times 8\)
\(R_{future} = 16\)

So, Rohan's age at that future point will be 16 years.

Verification

Let's check if our solution fits the original conditions:

  • Rohan's future age is 16, Nikhil's future age is 8.
  • Is Rohan 8 years older than Nikhil? \(16 - 8 = 8\). Yes, the age difference is 8 years.
  • Is Rohan twice as old as Nikhil? \(16 = 2 \times 8\). Yes, Rohan is twice as old as Nikhil.

Both conditions are satisfied by these ages.

Conclusion

When Rohan is twice as old as Nikhil, Rohan will be 16 years old.

Calculated Future Ages
Nikhil's Age (\(N_{future}\)) 8 years
Rohan's Age (\(R_{future}\)) 16 years

Comparing with Options

Our calculated age for Rohan is 16 years, which matches option 4.

Option Age Matches Calculation?
1 4 yr No
2 6 yr No
3 8 yr No
4 16 yr Yes

Revision Table

Concept Description Application in this Problem
Age Difference The difference between two people's ages remains constant over time. Used to set up the equation \(R_{future} - N_{future} = 8\).
Algebraic Equations Representing relationships between unknown quantities using variables. Used variables \(R_{future}\) and \(N_{future}\) and formed two equations based on the problem's conditions.
Solving System of Equations Finding values for variables that satisfy multiple equations simultaneously, often through substitution or elimination. Used substitution (\(R_{future} = 2 N_{future}\) into \(R_{future} = N_{future} + 8\)) to find \(N_{future}\) and then \(R_{future}\).

Additional Information

Age word problems are common in mathematics and can often be solved by setting up equations based on the information given. The key is to carefully identify the unknown quantities and the relationships between them at different points in time.

When dealing with age problems, remember that:

  • If the age difference between two people is \(d\) now, it will always be \(d\) in the future and was \(d\) in the past.
  • If someone is \(x\) years old now, in \(y\) years they will be \(x + y\) years old. In \(z\) years ago, they were \(x - z\) years old.
  • Phrases like "twice as old," "half as old," or "a third of the age" translate directly into multiplication or division in your equations.

In this specific problem, setting up the equations based on the future ages was the most direct path to the solution. We defined the future ages and wrote the conditions directly using those variables, avoiding the need to introduce a variable for the number of years from now.

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Similar Questions

  1. Anil and Beena are friends, and the difference between their ages is 5 years. Anil's father Dinesh is three times as old as Anil, and Beena is twice as old as her sister Charu. The ages of Dinesh and Charu differ by 45 years. If Beena is older than Anil, then find the sum of the present ages of both Dinesh and Charu.

  2. The ratio of the ages of two friends is 4: 3 which will become 6: 5 after 4 years. What will be the sum of their ages (in years) after 22 years from now?

  3. The present ages of Sweeta and Suman are in the ratio 4:5. After 6 years, the sum of their ages will be 54 years. Find the present age of Sweta.

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  6. In a family, the combined age of husband, wife, and a son is 90 years. The husband is ten older. The difference in the age of the husband and wife is 1/3rd of the age of their son. After 10 years, the age of the son would be half the age of his father. What is the present age of his mother (in years)?

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Important Questions from Age

  1. In 2002, Meenu's age was one-third of the age of Meera, whereas in 2010, Meenu's age was half the age of Meera. What is Meenu's year of birth?

  2. A watch loses 2 minutes in every 24 while another watch gains 2 minutes, in 24 hours. At a particular instant, the two watches showed an identical time. Which of the following statements is correct if 24- hour clock is

  3. The sum of the ages of 5 members comprising a family, 3 years ago was 80 years. The average age of the family today is the same as it was 3 years ago, because of an addition of a baby during the intervening period. How old is the baby ?

  4. 5 years ago, my sister's age was 5 times my age. Now it is 3 times only. What is my sister's present age (in years)?

  5. The sum of ages of a father and his son is 45 years. Five years ago, the product of their ages (in yrs.) was 124. The present age of father is :

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