Mod-12 counter needs
4 flip flops
A Mod-N counter is a type of digital counter that counts through N distinct states before repeating. The "Mod" stands for "modulo," meaning the counter resets after reaching a certain count, effectively operating modulo N. For example, a Mod-12 counter will count from 0 to 11 (12 distinct states) and then reset back to 0.
To determine the minimum number of flip-flops (sequential logic elements that store one bit of information) required for a Mod-N counter, we use the formula involving powers of 2. Each flip-flop can store one bit, meaning \(n\) flip-flops can store \(2^n\) unique states. To count N distinct states, the number of available states from the flip-flops must be greater than or equal to N.
The formula to find the minimum number of flip-flops (\(n\)) for a Mod-N counter is:
\[2^n \ge N\]
Here, \(N\) is the modulus of the counter (the number of distinct states).
For a Mod-12 counter, \(N = 12\). We need to find the smallest integer \(n\) such that \(2^n \ge 12\).
Let's test different values for \(n\):
Therefore, the minimum number of flip-flops required for a Mod-12 counter is 4.
| Number of Flip-Flops (\(n\)) | Maximum States (\(2^n\)) | Sufficient for Mod-12? |
|---|---|---|
| 1 | 2 | No (2 < 12) |
| 2 | 4 | No (4 < 12) |
| 3 | 8 | No (8 < 12) |
| 4 | 16 | Yes (16 ≥ 12) |
Based on this calculation, 4 flip-flops are necessary to implement a Mod-12 counter.
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The basic building block of sequential logic circuit is-
A single flip-flop is a modulo __________ counter.
For a JK Flip‐flop
A. When J = 0, K = 1, Q n+1 = 0
B. When J = 1, K = 1, Q n+1 = 1
C. When J = 1, K = 1, Q n+1 =\(\rm \overline{Q_n}\)
D. When J = 1, K = 0, Q n+1 = 1
E. When J = 1, K = 0, Q n+1 = 0
Choose the correct answer from the options given below: